jQuery Wait until async ajax calls are finished

孤街浪徒 提交于 2019-11-30 17:49:57

If using jQuery 1.5+, you can use jQuery.when() to accomplish this. Something like (shortened the ajax calls for brevity, just pass the objects as you're doing above)

$.when($.ajax("getText.asmx/ws_getText"), 
       $.ajax("getText.asmx/ws_getText")).done(function(a1,  a2){

   // a1 and a2 are arguments resolved for the 
   // first and second ajax requests, respectively
   var jqXHR = a1[2]; // arguments are [ "success", statusText, jqXHR ]
});

You don't know in which order they will return so if you were rolling this by hand, you would need to check the state of the other request and wait until it has returned.

You need to wire up the second call to be contained within the callback of your first ajax call. Like so:

success: function(msg)
{
    alert(msg.d.data);

    if(par02.length > 0)
    {
        // Your 2nd ajax call
    }
},

Since JavaScript doesnt run in multiple threads on the client, you can't block the thread until certain conditions are met.

user3673557

Using jquery

$.ajax({
        type: "POST",
        async:false, // ** CHANGED **
        url: "getText.asmx/ws_getText",
        data: parO1,
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        success: function (msg) {
            alert(msg.d.data);
        }
        , error: function () {
            chyba("chyba v požadavku", "df");
        }
    });
latoyale

Here is another answer on running dual ajax requests. Like Tejs, the user makes an ajax call within the success method...

The poster states You're better off having the success method launch a new ajax request.."

Having two $.ajax() calls in one script

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