问题
So I have a REST based service which is hosted at
http://localhost:35798/RestServiceImpl.svc/json/567
If I query that, I get the result as:
{"JSONDataResult":"You requested product 567"}
I need to store the whole JSON data into a PostgreSQL table:
CREATE TABLE "JsonTable"
(
"StoreJsonObject" json
)
If I want to parse the value field i.e. "You requested product 567", the program works (here I am using a different table whose column type is text):
<jdbc:postgresql-data-source name="PostgreSQL_Data_Source" user="username" password="pwd" url="jdbc:postgresql://localhost:5432/TestDB" transactionIsolation="UNSPECIFIED" doc:name="PostgreSQL Data Source"/>
<jdbc:connector name="PostgreSQL_Connector" dataSource-ref="PostgreSQL_Data_Source" validateConnections="true" queryTimeout="-1" pollingFrequency="0" doc:name="Database">
<jdbc:query key="InsertRecord" value="INSERT INTO "AnotherJSonTable"("StoreJsonObject") VALUES (#[message.payload])"/>
</jdbc:connector>
<flow name="testRestFlow1" doc:name="testRestFlow1">
<http:inbound-endpoint exchange-pattern="request-response" address="http://localhost:8082/index.html" doc:name="HTTP"/>
<http:rest-service-component httpMethod="GET" serviceUrl="http://localhost:35798/RestServiceImpl.svc/json/567">
</http:rest-service-component>
<json:json-to-object-transformer returnClass="java.util.Map" doc:name="JSON to Object"/>
<expression-transformer expression="#[message.payload.JSONDataResult]" doc:name="Expression"/>
<jdbc:outbound-endpoint exchange-pattern="one-way" queryKey="InsertRecord" queryTimeout="-1" connector-ref="PostgreSQL_Connector" doc:name="Database"/>
</flow>
But how to store the entire JSON object ({"JSONDataResult":"You requested product 567"}).
What do I need to change in the "expression-transformer"?
If I do:
<jdbc:query key="InsertRecord" value="INSERT INTO "JsonTable"("StoreJsonObject") VALUES (#[message.payload])"/>
<expression-transformer expression="#[message.payload]" doc:name="Expression"/>
I receive exception:
Root Exception stack trace:
org.postgresql.util.PSQLException: No hstore extension installed.
at org.postgresql.jdbc2.AbstractJdbc2Statement.setMap(AbstractJdbc2Statement.java:1713)
at org.postgresql.jdbc2.AbstractJdbc2Statement.setObject(AbstractJdbc2Statement.java:1916)
at org.postgresql.jdbc3g.AbstractJdbc3gStatement.setObject(AbstractJdbc3gStatement.java:36)
+ 3 more (set debug level logging or '-Dmule.verbose.exceptions=true' for everything)
********************************************************************************
INFO 2012-12-24 15:48:31,945 [[testrest].connector.file.mule.default.receiver.01] org.mule.transport.file.FileMessageReceiver: Lock obtained on file: C:\Users\niladri.biswas\Desktop\input\all_winjs_ui_controls.txt
INFO 2012-12-24 15:48:31,945 [[testrest].testRestFlow1.stage1.02] org.mule.transport.http.components.RestServiceWrapper: Invoking REST service: http://localhost:35798/RestServiceImpl.svc/json/567
ERROR 2012-12-24 15:48:31,992 [[testrest].PostgreSQL_Connector.dispatcher.01] org.mule.exception.DefaultMessagingExceptionStrategy:
********************************************************************************
Message : Failed to route event via endpoint: DefaultOutboundEndpoint{endpointUri=jdbc://InsertRecord, connector=JdbcConnector
{
name=PostgreSQL_Connector
lifecycle=start
this=15e7ea6
numberOfConcurrentTransactedReceivers=4
createMultipleTransactedReceivers=false
connected=true
supportedProtocols=[jdbc]
serviceOverrides=<none>
}
, name='endpoint.jdbc.InsertRecord', mep=ONE_WAY, properties={queryTimeout=-1}, transactionConfig=Transaction{factory=null, action=INDIFFERENT, timeout=0}, deleteUnacceptedMessages=false, initialState=started, responseTimeout=10000, endpointEncoding=UTF-8, disableTransportTransformer=false}. Message payload is of type: LinkedHashMap
Code : MULE_ERROR--2
--------------------------------------------------------------------------------
Also the record should be inserted only once after reading from the service and not multiple times.
回答1:
Since you want to store the whole JSON, there is no need to deserialize it as an object: I suggest you simply transform the HTTP-streamed payload into a java.lang.String
and insert it as-is in the DB.
This would done like that:
<jdbc:postgresql-data-source name="PostgreSQL_Data_Source"
user="username" password="pwd" url="jdbc:postgresql://localhost:5432/TestDB"
transactionIsolation="UNSPECIFIED" doc:name="PostgreSQL Data Source" />
<jdbc:connector name="PostgreSQL_Connector" dataSource-ref="PostgreSQL_Data_Source"
validateConnections="true" queryTimeout="-1" pollingFrequency="0"
doc:name="Database">
<jdbc:query key="InsertRecord"
value="INSERT INTO "AnotherJSonTable"("StoreJsonObject") VALUES (CAST(#[message.payload] AS json))" />
</jdbc:connector>
<flow name="testRestFlow1" doc:name="testRestFlow1">
<http:inbound-endpoint exchange-pattern="request-response"
address="http://localhost:8082/index.html" doc:name="HTTP" />
<http:rest-service-component httpMethod="GET"
serviceUrl="http://localhost:35798/RestServiceImpl.svc/json/567" />
<object-to-string-transformer />
<jdbc:outbound-endpoint exchange-pattern="one-way"
queryKey="InsertRecord" queryTimeout="-1" connector-ref="PostgreSQL_Connector"
doc:name="Database" />
</flow>
来源:https://stackoverflow.com/questions/14003046/how-to-read-rest-service-that-returns-json-object-and-store-the-same-into-postgr