问题
In matrix multiplication, assume that the A is a 3 x 2 matrix (3 rows, 2 columns ) and B is a 2 x 4 matrix (2 rows, 4 columns ), then if a matrix C = A * B, then C should have 3 rows and 4 columns. Why does numpy not do this multiplication? When I try the following code I get an error : ValueError: operands could not be broadcast together with shapes (3,2) (2,4)
a = np.ones((3,2))
b = np.ones((2,4))
print a*b
I try with transposing A and B and alwasy get the same answer. Why? How do I do the matrix multiplication in this case?
回答1:
The * operator for numpy arrays is element wise multiplication (similar to the Hadamard product for arrays of the same dimension), not matrix multiply.
For example:
>>> a
array([[0],
[1],
[2]])
>>> b
array([0, 1, 2])
>>> a*b
array([[0, 0, 0],
[0, 1, 2],
[0, 2, 4]])
For matrix multiply with numpy arrays:
>>> a = np.ones((3,2))
>>> b = np.ones((2,4))
>>> np.dot(a,b)
array([[ 2., 2., 2., 2.],
[ 2., 2., 2., 2.],
[ 2., 2., 2., 2.]])
In addition you can use the matrix class:
>>> a=np.matrix(np.ones((3,2)))
>>> b=np.matrix(np.ones((2,4)))
>>> a*b
matrix([[ 2., 2., 2., 2.],
[ 2., 2., 2., 2.],
[ 2., 2., 2., 2.]])
More information on broadcasting numpy arrays can be found here, and more information on the matrix class can be found here.
来源：https://stackoverflow.com/questions/18255583/numpy-matrix-multiplication-shapes