Mapping flat JSON/Dictionary to model (containing sub classes)

谁都会走 提交于 2019-11-30 16:04:18

问题


I want to turn a flat json string into a model, the destination class has subclasses, and the flat json has all of the sub class objects with prefix; like "{classname}.{property}".

{
    "FirstName": "Joey",
    "LastName": "Billy",
    "EmploymentDetails.JobTitle": "JobTitle",
    "EmploymentDetails.StartDate": "2015-01-01T00:00:00",
    "ContactDetails.HouseNumberName": "10",
    "ContactDetails.Road": "Road"
}

This is my destination class:

public class Person {
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public virtual EmploymentDetails EmploymentDetails { get;set;}
    public virtual ContactDetails ContactDetails { get;set;}
}
public class EmploymentDetails {
    public string JobTitle { get; set; }
    public DateTime StartDate { get; set; }
}
public class ContactDetails {
    public string HouseNumberName { get; set; }
    public string Road { get; set; }
}

I tried the following:

public static void main() {
    var json = @"{""FirstName"": ""Joey"",""LastName"": ""Billy"",""EmploymentDetails.JobTitle"": ""JobTitle"",""EmploymentDetails.StartDate"": ""2015-01-01T00:00:00"",""ContactDetails.HouseNumberName"": ""10"",""ContactDetails.Road"": ""Road"",}";

    //try using AutoMapper
    Mapper.CreateMap<string,Person>();
    var personModel = Mapper.Map<Person>(json);
    //just returns null values

    //try using Newtonsoft
    personModel = Newtonsoft.Json.JsonConvert.DeserializeObject<Person>(json);
    //fills values but obviously returns no nested data
}

I know that Automapper has RecognizePrefix and RecognizeDestinationPrefix, but AutoMapper seems to only care if it's in the orignal object, and not a sub class.

Potentially I could take my JSON string and make it a Dictionary, but even then I don't know how to map it to a model with sub classes.

There was hope that I could have an infinite amount of sub classes and the JSON string could just map the flat JSON model to a model.


回答1:


You can make a JsonConverter that does this in a generic way, using a ContractResolver to group and populate properties in the class being deserialized or its contained classes as appropriate.

You didn't ask for serialization, only deserialization, so that's what this does:

public class JsonFlatteningConverter : JsonConverter
{
    readonly IContractResolver resolver;

    public JsonFlatteningConverter(IContractResolver resolver)
    {
        if (resolver == null)
            throw new ArgumentNullException();
        this.resolver = resolver;
    }

    public override bool CanConvert(Type objectType)
    {
        return resolver.ResolveContract(objectType) is JsonObjectContract;
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        if (reader.TokenType == JsonToken.Null)
            return null;

        JObject jObject = JObject.Load(reader);
        var contract = (JsonObjectContract)resolver.ResolveContract(objectType); // Throw an InvalidCastException if this object does not map to a JObject.

        existingValue = existingValue ?? contract.DefaultCreator();

        if (jObject.Count == 0)
            return existingValue;

        var groups = jObject.Properties().GroupBy(p => p.Name.Contains('.') ? p.Name.Split('.').FirstOrDefault() : null).ToArray();
        foreach (var group in groups)
        {
            if (string.IsNullOrEmpty(group.Key))
            {
                var subObj = new JObject(group);
                using (var subReader = subObj.CreateReader())
                    serializer.Populate(subReader, existingValue);
            }
            else
            {
                var jsonProperty = contract.Properties[group.Key];
                if (jsonProperty == null || !jsonProperty.Writable)
                    continue;
                if (jsonProperty != null)
                {
                    var subObj = new JObject(group.Select(p => new JProperty(p.Name.Substring(group.Key.Length + 1), p.Value)));
                    using (var subReader = subObj.CreateReader())
                    {
                        var propertyValue = serializer.Deserialize(subReader, jsonProperty.PropertyType);
                        jsonProperty.ValueProvider.SetValue(existingValue, propertyValue);
                    }
                }
            }
        }
        return existingValue;
    }

    public override bool CanWrite { get { return false; } }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

And then use it thusly:

        var resolver = new DefaultContractResolver();
        var settings = new JsonSerializerSettings { ContractResolver = resolver, Converters = new JsonConverter[] { new JsonFlatteningConverter(resolver) } };

        var person = JsonConvert.DeserializeObject<Person>(json, settings);

Prototype fiddle.



来源:https://stackoverflow.com/questions/33026829/mapping-flat-json-dictionary-to-model-containing-sub-classes

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!