iterate row by row COUNTIF using ArrayFormula on Google Sheets

Question

I am trying to iterate a COUNTIF formula that counts the number of cells in each row containing numbers greater than 4. I am trying to use ArrayFormula to do this but it isn't working.

Unfortunately it counts ALL the cells matching the condition across the entire range B2:G39 resulting in 26 being entered in each row of column K rather than row by row count i.e. number of cells >4 in B2:G2 entered in K2, number of cells >4 in B3:G3 entered in K3

This is the formula

=ARRAY_CONSTRAIN(arrayformula( if( row(H:H)=1, "Number of cells >4",COUNTIF(A2:G39,">4"))),39,1)

Here is a spreadsheet that includes sample data and my formula

Answer 1

Try entering this in cell K2:

=ARRAYFORMULA(IF(ISBLANK(A2:A),IFERROR(1/0),MMULT(SIGN(A2:G>4),SIGN(TRANSPOSE(A2:G2)))))

By putting your data into matrix form, you can use the MMULT and SIGN functions with ARRAYFORMULA to achieve the conditional count over rows you're looking for.

Answer 2

Sample File

I found that mmult is very slow and may cause your file loading a long time. I suggest using len + join (with a query) instead (speed is not tested):

={"RegexReplace-Len..."; ArrayFormula(LEN(REGEXREPLACE(TRANSPOSE(QUERY(TRANSPOSE(FILTER(--(A2:P>5),A2:A<>"")),,100500)),"[ 0]", "")))}

Also here's a solution by JPV:

=filter(COUNTIF(IF(A2:P>5, ROW(A2:A)), ROW(A2:A)), A2:A<>"")

Change A2:P to your range, A2:A to a key column with no blank cells.