Supposing all I have is the column A below
+ +
A | B | C
+--------------|---------|----------+
| |
X, Y, Z | X | 3
| |
X, Z | Y | 2
| |
X, Y | Z | 2
+ +
How do I generate columns B and C - where the B column grabs the unique elements from A, and the C column generates a count of those values.
=ArrayFormula(QUERY(TRANSPOSE(SPLIT(JOIN(",",A:A),",")&{"";""}),"select Col1, count(Col2) group by Col1 label count(Col2) ''",0))
Without hidden cells is possible to do it with an alternative method than the one proposed by Adam (that did not work in my case). I have tested it with google spreadsheets (from data coming from a google form using multiple selection answers):
=UNIQUE(TRANSPOSE(SPLIT(JOIN(", ";A2:A);", ";FALSE)))
Explanation goes as follows:
- JOIN to mix all the values from the A column (except A1 that could be the header of the column, if not, substitute it by A:A) separated by a coma
- SPLIT to separate all the mixed values by their comas
- TRANSPOSE to transformate the column into rows and viceversa
- UNIQUE to avoid repeated values
Take into account that my "," coma includes and space character i.e., ", " to avoid incorrect unique values because "Z" y not equal to " Z".
Is it possible to create a hidden sheet?
If yes, 1) use the SPLIT() function to separate the values into columns and 2) use COUNTIF() on the hidden sheet to get the number of values
来源：https://stackoverflow.com/questions/20715099/getting-the-count-and-unique-values-of-a-column-of-comma-separated-values