WPF ContextMenu itemtemplate, menuitem inside menuitem

可紊 提交于 2019-11-30 14:23:39

Because MenuItem is the container type and when it translates your view model into visual item it will wrap your template in MenuItem. In the same way ListBox will create ListBoxItem or ListView will use ListViewItem. To bind properties of the wrapper you need to use ItemContainerStyle

<ContextMenu ItemsSource="{Binding TestItems}">
   <ContextMenu.ItemContainerStyle>
      <Style TargetType="{x:Type MenuItem}">
         <Setter Property="IsChecked" Value="{Binding IsSelected}"/>
         <Setter Property="Header" Value="{Binding Header}"/>
      </Style>
   </ContextMenu.ItemContainerStyle>
</ContextMenu>

or, if you prefer, you can do it partially with ItemTemplate and ItemContainerStyle

<ContextMenu ItemsSource="{Binding TestItems}">
   <ContextMenu.ItemTemplate>
      <DataTemplate>
         <TextBlock Text="{Binding Header}"/>
      </DataTemplate>
   </ContextMenu.ItemTemplate>
   <ContextMenu.ItemContainerStyle>
      <Style TargetType="{x:Type MenuItem}">
         <Setter Property="IsChecked" Value="{Binding IsSelected}"/>
      </Style>
   </ContextMenu.ItemContainerStyle>
</ContextMenu>

In this scenario whatever is in ItemTemplate will become MenuItem.Header but IsChecked property still needs to be bound in ItemContainerStyle

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!