问题
Basic problem
I have a bunch of records and I need to get latest (most recent) and the oldest (least recent).
When googling I found this topic where I saw a couple of queries:
// option 1
Tweet.findOne({}, [], { $orderby : { 'created_at' : -1 } }, function(err, post) {
console.log( post );
});
// option 2
Tweet.find({}, [], {sort:[['arrival',-1]]}, function(err, post) {
console.log( post );
});
Unfortunatly they both error:
TypeError: Invalid select() argument. Must be a string or object.
The link also has this one:
Tweet.find().sort('_id','descending').limit(15).find(function(err, post) {
console.log( post );
});
and that one errors:
TypeError: Invalid sort() argument. Must be a string or object.
So how can I get those records?
Timespan
Even more ideally I just want the difference in time (seconds?) between the oldest and the newest record, but I have no clue on how to start making a query like that.
This is the schema:
var Tweet = new Schema({
body: String
, fid: { type: String, index: { unique: true } }
, username: { type: String, index: true }
, userid: Number
, created_at: Date
, source: String
});
I'm pretty sure I have the most recent version of mongoDB and mongoose.
EDIT
This is how I calc the timespan based on the answer provided by JohnnyHK:
var calcDays = function( cb ) {
var getOldest = function( cb ) {
Tweet.findOne({}, {}, { sort: { 'created_at' : 1 } }, function(err, post) {
cb( null, post.created_at.getTime() );
});
}
, getNewest = function( cb ) {
Tweet.findOne({}, {}, { sort: { 'created_at' : -1 } }, function(err, post) {
cb( null, post.created_at.getTime() );
});
}
async.parallel({
oldest: getOldest
, newest: getNewest
}
, function( err, results ) {
var days = ( results.newest - results.oldest ) / 1000 / 60 / 60 / 24;
// days = Math.round( days );
cb( null, days );
}
);
}
回答1:
Mongoose 3.x is complaining about the []
parameter in your findOne
calls as the array format is no longer supported for the parameter that selects the fields to include.
Try this instead to find the newest:
Tweet.findOne({}, {}, { sort: { 'created_at' : -1 } }, function(err, post) {
console.log( post );
});
Change the -1
to a 1
to find the oldest.
But because you're not using any field selection, it's somewhat cleaner to chain a couple calls together:
Tweet.findOne().sort({created_at: -1}).exec(function(err, post) { ... });
Or even pass a string to sort:
Tweet.findOne().sort('-created_at').exec(function(err, post) { ... });
回答2:
Tested on mongoose 5.4.x
Get 10 latest documents
MySchema.find().sort({ _id: -1 }).limit(10)
Get 10 oldest documents
MySchema.find().sort({ _id: 1 }).limit(10)
回答3:
for version ~3.8 mongoose
to find the last entry
model.findOne().sort({ field: 'asc', _id: -1 }).limit(1)
or using
model.findOne().sort({ field: -_id }).limit(1)
回答4:
We have method called sort using that we can able to get first element(old document) which means 1 for sort field or last element(new document) which means -1 for sort field of collection.
回答5:
collectionName.findOne().sort({$natural: -1}).limit(1).exec(function(err, res){
if(err){
console.log(err);
}
else{
console.log(res);
}
}
This will give you the last document recorded on the database. Just follow the same concept.
来源:https://stackoverflow.com/questions/12467102/how-to-get-the-latest-and-oldest-record-in-mongoose-js-or-just-the-timespan-bet