Default Struct Initialization in C++

*爱你&永不变心* 提交于 2019-11-30 09:28:47

The first one leaves the values uninitialised; the second initialises them to zero. This is only the case for POD types, which have no constructors.

I suppose nothing at all. Foo() is allowed, even if it makes no sense... I've tried to change struct into class and tried a diff on the generated exe, and they resulted to be the same, meaning that a class without method is like a struct from a practical and "effective" point of view.

But: if you use only one of the alternative, keeping struct or class no matter, it happens that new Foo and new Foo() gives executables which differ! (At least using g++) I.e.

struct Foo { int i; double d; }
int main() { Foo *f1 = new Foo; delete f1; }

is compiled into somehing different from

struct Foo { int i; double d; }
int main() { Foo *f1 = new Foo(); delete f1; }

and the same happens with class instead of struct. To know where the difference is we should look at the generated code... and to know if it is a g++ idiosincracy or not, I should try another compiler but I have only gcc and no time now to analyse the asm output of g++...

Anyway from a "functional" (practical) point of view, it is the same thing.

Add

At the end it is always better to know or do deeper investigation for some common human problems on Q/A sites... the only difference in the code generated by g++ in () and no () cases,

    movl    $0, (%eax)
    fldz
    fstpl   4(%eax)

which is a fragment that initializes to 0/0.0 the int and the double of the struct... so Seymour knows it better (but I could have discovered it without knowing if I had taken a look at the asm first!)

Elliott

Per the link I posted.

In C++ the only difference between a class and a struct is that class-members are private by default, while struct-members default to public. So structures can have constructors, and the syntax is the same as for classes.

Struct Constructor Info

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