问题

I have a program that may have a lengthy execution. In the main module I have the following:

import signal
def run_program()
   ...time consuming execution...

def Exit_gracefully(signal, frame):
    ... log exiting information ...
    ... close any open files ...
    sys.exit(0)

if __name__ == \'__main__\':
    signal.signal(signal.SIGINT, Exit_gracefully)
    run_program()

This works fine, but I\'d like the possibility to pause execution upon catching SIGINT, prompting the user if they would really like to quit, and resuming where I left off in run_program() if they decide they don\'t want to quit.

The only way I can think of doing this is running the program in a separate thread, keeping the main thread waiting on it and ready to catch SIGINT. If the user wants to quit the main thread can do cleanup and kill the child thread.

Is there a simpler way?

回答1:

The python signal handlers do not seem to be real signal handlers; that is they happen after the fact, in the normal flow and after the C handler has already returned. Thus you'd try to put your quit logic within the signal handler. As the signal handler runs in the main thread, it will block execution there too.

Something like this seems to work nicely.

import signal
import time
import sys

def run_program():
    while True:
        time.sleep(1)
        print("a")

def exit_gracefully(signum, frame):
    # restore the original signal handler as otherwise evil things will happen
    # in raw_input when CTRL+C is pressed, and our signal handler is not re-entrant
    signal.signal(signal.SIGINT, original_sigint)

    try:
        if raw_input("\nReally quit? (y/n)> ").lower().startswith('y'):
            sys.exit(1)

    except KeyboardInterrupt:
        print("Ok ok, quitting")
        sys.exit(1)

    # restore the exit gracefully handler here    
    signal.signal(signal.SIGINT, exit_gracefully)

if __name__ == '__main__':
    # store the original SIGINT handler
    original_sigint = signal.getsignal(signal.SIGINT)
    signal.signal(signal.SIGINT, exit_gracefully)
    run_program()

The code restores the original signal handler for the duration of raw_input; raw_input itself is not re-entrable, and re-entering it will lead to RuntimeError: can't re-enter readline being raised from time.sleep which is something we don't want as it is harder to catch than KeyboardInterrupt. Rather, we let 2 consecutive Ctrl-C's to raise KeyboardInterrupt.

回答2:

from https://gist.github.com/rtfpessoa/e3b1fe0bbfcd8ac853bf

#!/usr/bin/env python

import signal
import sys

def signal_handler(signal, frame):
  # your code here
  sys.exit(0)

signal.signal(signal.SIGINT, signal_handler)

Bye!

回答3:

when procedure end then do something

suppose you just want to the procedure will do something after the task end

import time

class TestTask:
    def __init__(self, msg: str):
        self.msg = msg

    def __enter__(self):
        print(f'Task Start!:{self.msg}')
        return self

    def __exit__(self, exc_type, exc_val, exc_tb):
        print('Task End!')

    @staticmethod
    def do_something():
        try:
            time.sleep(5)
        except:
            pass

with TestTask('Hello World') as task:
    task.do_something()

when the process leaves with that will run __exit__ even with KeyboardInterrupt happen that are same.

if you don't like to see the error, add try ... except ...

@staticmethod
def do_something():
    try:
        time.sleep(5)
    except:
        pass

pause, continue, reset, and etc.

I don't have a perfect solution, but it may be useful to you.

It's means divided your process to many subprocesses and save it that finished.it will not be executed again since you find it already done.

import time
from enum import Enum

class Action(Enum):
    EXIT = 0
    CONTINUE = 1
    RESET = 2

class TestTask:
    def __init__(self, msg: str):
        self.msg = msg

    def __enter__(self):
        print(f'Task Start!:{self.msg}')
        return self

    def __exit__(self, exc_type, exc_val, exc_tb):
        print('Task End!')

    def do_something(self):
        tuple_job = (self._foo, self._bar)  # implement by yourself
        list_job_state = [0] * len(tuple_job)
        dict_keep = {}  # If there is a need to communicate between jobs, and you don’t want to use class members, you can use this method.
        while 1:
            try:
                for idx, cur_process in enumerate(tuple_job):
                    if not list_job_state[idx]:
                        cur_process(dict_keep)
                        list_job_state[idx] = True
                if all(list_job_state):
                    print('100%')
                    break
            except KeyboardInterrupt:
                print('KeyboardInterrupt. input action:')
                msg = '\n\t'.join([f"{action + ':':<10}{str(act_number)}" for act_number, action in
                                   enumerate([name for name in vars(Action) if not name.startswith('_')])
                                   ])
                case = Action(int(input(f'\t{msg}\n:')))
                if case == Action.EXIT:
                    break
                if case == Action.RESET:
                    list_job_state = [0] * len(tuple_job)

    @staticmethod
    def _foo(keep_dict: dict) -> bool:  # implement by yourself
        time.sleep(2)
        print('1%')
        print('2%')
        print('...')
        print('60%')
        keep_dict['status_1'] = 'status_1'
        return True

    @staticmethod
    def _bar(keep_dict: dict) -> bool:  # implement by yourself
        time.sleep(2)
        print('61%')
        print(keep_dict.get('status_1'))
        print('...')
        print('99%')
        return True

with TestTask('Hello World') as task:
    task.do_something()

console

input action number:2
Task Start!:Hello World
1%
2%
...
60%
KeyboardInterrupt. input action:
        EXIT:     0
        CONTINUE: 1
        RESET:    2
:1
61%
status_1
...
99%
100%
Task End!

来源：https://stackoverflow.com/questions/18114560/python-catch-ctrl-c-command-prompt-really-want-to-quit-y-n-resume-executi

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python