UIButton inside a view that has a UITapGestureRecognizer

半城伤御伤魂 提交于 2019-11-26 10:59:56

You can set your controller or view (whichever creates the gesture recognizer) as the delegate of the UITapGestureRecognizer. Then in the delegate you can implement -gestureRecognizer:shouldReceiveTouch:. In your implementation you can test if the touch belongs to your new subview, and if it does, instruct the gesture recognizer to ignore it. Something like the following:

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
    // test if our control subview is on-screen
    if (self.controlSubview.superview != nil) {
        if ([touch.view isDescendantOfView:self.controlSubview]) {
            // we touched our control surface
            return NO; // ignore the touch
        }
    }
    return YES; // handle the touch
}

As a follow up to Casey's follow up to Kevin Ballard's answer:

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
        if ([touch.view isKindOfClass:[UIControl class]]) {
            // we touched a button, slider, or other UIControl
            return NO; // ignore the touch
        }
    return YES; // handle the touch
}

This basically makes all user input types of controls like buttons, sliders, etc. work

ejazz

Found this answer here: link

You can also use

tapRecognizer.cancelsTouchesInView = NO;

Which prevents the tap recognizer to be the only one to catch all the taps

UPDATE - Michael mentioned the link to the documentation describing this property: cancelsTouchesInView

Casey

As a follow up to Kevin Ballard's answer, I had this same problem and ended up using this code:

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
    if ([touch.view isKindOfClass:[UIButton class]]){
        return NO;
    }
    return YES;
}

It has the same effect but this will work on any UIButton at any view depth (my UIButton was several views deep and the UIGestureRecognizer's delegate didn't have a reference to it.)

In iOS 6.0 and later, default control actions prevent overlapping gesture recognizer behavior. For example, the default action for a button is a single tap. If you have a single tap gesture recognizer attached to a button’s parent view, and the user taps the button, then the button’s action method receives the touch event instead of the gesture recognizer. This applies only to gesture recognition that overlaps the default action for a control, which includes:.....

From Apple's API doc

These answers were incomplete. I had to read multiple posts as to how to use this boolean operation.

In your *.h file add this

@interface v1ViewController : UIViewController <UIGestureRecognizerDelegate>

In your *.m file add this

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {

    NSLog(@"went here ...");

    if ([touch.view isKindOfClass:[UIControl class]])
    {
        // we touched a button, slider, or other UIControl
        return NO; // ignore the touch
    }
    return YES; // handle the touch
}
- (void)viewDidLoad
{
    [super viewDidLoad];
    // Do any additional setup after loading the view, typically from a nib.



    //tap gestrure
    UITapGestureRecognizer *tapGestRecog = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(screenTappedOnce)];
    [tapGestRecog setNumberOfTapsRequired:1];
    [self.view addGestureRecognizer:tapGestRecog];


// This line is very important. if You don't add it then your boolean operation will never get called
tapGestRecog.delegate = self;

}


-(IBAction) screenTappedOnce
{
    NSLog(@"screenTappedOnce ...");

}
MindMirror

Found another way to do it from here. It detects the touch whether inside each button or not.

(1) pointInside:withEvent: (2) locationInView:

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer 
       shouldReceiveTouch:(UITouch *)touch {
    // Don't recognize taps in the buttons
    return (![self.button1 pointInside:[touch locationInView:self.button1] withEvent:nil] &&
            ![self.button2 pointInside:[touch locationInView:self.button2] withEvent:nil] &&
            ![self.button3 pointInside:[touch locationInView:self.button3] withEvent:nil]);
}
John Riselvato

Here's the Swift version of Lily Ballard's answer that worked for me:

func gestureRecognizer(gestureRecognizer: UIGestureRecognizer, shouldReceiveTouch touch: UITouch) -> Bool {
    if (scrollView.superview != nil) {
        if ((touch.view?.isDescendantOfView(scrollView)) != nil) { return false }
    }
    return true
}

You can stop the UITapGestureRecognizer from cancelling other events (such as the tap on your button) by setting the following boolean:

    [tapRecognizer setCancelsTouchesInView:NO];

If your scenario is like this:

You have a simple view and some UIButtons,UITextField controls added as subviews to that view. Now you want to dismiss the keyboard when you touch anywhere else on the view except on the controls(subviews you added)

Then Solution is:

Add the following method to your XYZViewController.m(which has your view)

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
    [self.view endEditing:YES];
}
Clay Bridges

Optimizing cdasher's answer, you get

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer
       shouldReceiveTouch:(UITouch *)touch 
{
    return ![touch.view isKindOfClass:[UIControl class]];
}
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