How do you append new line(\n\r) character in StringBuilder
?
I would make use of Environment.NewLine Property
Something like
StringBuilder sb = new StringBuilder();
sb.AppendFormat("Foo{0}Bar", Environment.NewLine);
string s = sb.ToString();
Or
StringBuilder sb = new StringBuilder();
sb.Append("Foo");
sb.Append("Foo2");
sb.Append(Environment.NewLine);
sb.Append("Bar");
string s = sb.ToString();
EDIT:
If you wish to have a new line after each append, you can have a look at @Ben Voigt answer.
also, using StringBuilder.AppendLine method.
It will append \n
in Linux instead \r\n
.
Use String builder append line inbuilt functions
StringBuilder sb = new StringBuilder();
sb.AppendLine("first line ");
sb.AppendLine("Second line ");
sb.AppendLine("third line ");
output
firstline Second line third line
For multiple lines the best way I find is to do this:
IEnumerable<string> lines = new List<string>
{
string.Format("{{ line with formatting... {0} }}", id),
"line 2",
"line 3"
};
StringBuilder sb = new StringBuilder();
foreach(var line in lines)
sb.AppendLine(line);
In this way you don't have to clutter the screen with the Environment.NewLine or AppendLine() repeated multiple times. It will also be less error prone than having to remember to type them.
StringBuilder sb = new StringBuilder();
You can use sb.AppendLine() or sb.Append(Environment.NewLine);
Why not just create an extension for the stringbuilder class?
Public Module Extensions
<Extension()>
Public Sub AppendFormatWithNewLine(ByRef sb As System.Text.StringBuilder, ByVal format As String, ParamArray values() As Object)
sb.AppendLine(String.Format(format, values))
End Sub
End Module
来源:https://stackoverflow.com/questions/2617752/newline-character-in-stringbuilder