问题
Here is my question i have tuple1=[(1, 3), (3, 2), (2, 1)]
i want to sort tuple based on last digit of each tuple so the resultant will look like this
output=[(2, 1), (3, 2), (1, 3)]
below is my code
i=0
for x in tuples:
c.append(x[len(x)-1])
last=sorted(c)
for y in last.iteritems():
if(y in x[len(x)-1]):
print x
#b.insert(i,x)
i=i+1
after running iam getting an error message
Traceback (most recent call last):
File "x.py", line 47, in <module>
sort_last([(1, 3), (3, 2), (2, 1)])
File "x.py", line 35, in sort_last
if(y in x[len(x)-1]):
TypeError: argument of type 'int' is not iterable
回答1:
Specify the key
argument in the sorted
function.
>>> tuple1=[(1, 3), (3, 2), (2, 1)]
>>> output = sorted(tuple1, key=lambda x: x[-1])
>>> print output
[(2, 1), (3, 2), (1, 3)]
The sorted
function (as well as the list.sort
method) has an optional key
argument which specifies what to sort the list on.
来源:https://stackoverflow.com/questions/14829300/python-tuples-sorting-based-on-last-element