Pandas Counting Unique Rows

问题

I have a pandas data frame similar to:

ColA ColB
1    1
1    1
1    1
1    2
1    2
2    1
3    2

I want an output that has the same function as Counter. I need to know how many time each row appears (with all of the columns being the same.

In this case the proper output would be:

ColA ColB Count
1    1    3
1    2    2
2    1    1
3    2    1

I have tried something of the sort:

df.groupby(['ColA','ColB']).ColA.count()

but this gives me some ugly output I am having trouble formatting

回答1:

You can use size with reset_index:

print df.groupby(['ColA','ColB']).size().reset_index(name='Count')
   ColA  ColB  Count
0     1     1      3
1     1     2      2
2     2     1      1
3     3     2      1

回答2:

I only needed to count the unique rows and have used this alternative:

len(df[['ColA','ColB']].drop_duplicates())

For this task, on my data, it was twice faster than len(df.groupby(['ColA','ColB'])) like in the above, more general solution.

来源：https://stackoverflow.com/questions/36018851/pandas-counting-unique-rows