How to get the return value of xcodebuild?

问题

I'm using xcodebuild inside a bash script on a continuous integration server.

I would like to know when a build as failed in the script, so I can exit prematurely from it and mark the build as failed.

xcodebuild displays a BUILD FAILED message to the console, but I don't succeed in getting a return value.

How can I achieve this?

Thanks in advance

回答1:

I solved my problem using this command: xcodebuild -... || exit 1

回答2:

xcodebuild always returns 0, regardless of the actual test result. You should check for either ** BUILD FAILED ** or ** BUILD SUCCEEDED ** in the output to know whether tests pass or not.

回答3:

You can use the "$?" variable to get the return code of the previous command.

xcodebuild -...
if [[ $? == 0 ]]; then
    echo "Success"
else
    echo "Failed"
fi

回答4:

Xcodebuild can return any of the error codes listed here and not restricted to EX_OK (or int 0).

However, I learnt from solution provided by Dmitry and modified as following. It works for me and I hope it could be helpful.

xcodebuild -project ......
     if test $? -eq 0
     then
        echo "Success"
     else
        echo "Failed"
     fi

回答5:

Maybe it's not because of the xcodebuild not returning non-zero when build failed. Your shell script continuing to run regardless of the returning-error line might be the result of that you didn't run the script with a "-e" option.

Try put #!/bin/bash -e ahead of the script file.

回答6:

Whether the compiled product （.a or .ipa file）exists

来源：https://stackoverflow.com/questions/7363459/how-to-get-the-return-value-of-xcodebuild

标签

xcodebuild