问题
I have an external API that returns me dates as long
s, represented as milliseconds since the beginning of the Epoch.
With the old style Java API, I would simply construct a Date
from it with
Date myDate = new Date(startDateLong)
What is the equivalent in Java 8\'s LocalDate
/LocalDateTime
classes?
I am interested in converting the point in time represented by the long
to a LocalDate
in my current local timezone.
回答1:
If you have the milliseconds since the Epoch and want convert them to a local date using the current local timezone, you can use
LocalDate date =
Instant.ofEpochMilli(longValue).atZone(ZoneId.systemDefault()).toLocalDate();
but keep in mind that even the system’s default time zone may change, thus the same long
value may produce different result in subsequent runs, even on the same machine.
Further, keep in mind that LocalDate
, unlike java.util.Date
, really represents a date, not a date and time.
Otherwise, you may use a LocalDateTime
:
LocalDateTime date =
LocalDateTime.ofInstant(Instant.ofEpochMilli(longValue), ZoneId.systemDefault());
回答2:
You can start with Instant.ofEpochMilli(long):
LocalDate date =
Instant.ofEpochMilli(startDateLong)
.atZone(ZoneId.systemDefault())
.toLocalDate();
回答3:
I think I have a better answer.
new Timestamp(longEpochTime).toLocalDateTime();
回答4:
Timezones and stuff aside, a very simple alternative to new Date(startDateLong)
could be LocalDate.ofEpochDay(startDateLong / 86400000L)
回答5:
In a specific case where your epoch seconds timestamp comes from SQL or is related to SQL somehow, you can obtain it like this:
long startDateLong = <...>
LocalDate theDate = new java.sql.Date(startDateLong).toLocalDate();
来源:https://stackoverflow.com/questions/35183146/how-can-i-create-a-java-8-localdate-from-a-long-epoch-time-in-milliseconds