In a bash script, how do I sanitize user input?

纵饮孤独 提交于 2019-11-29 22:50:21

As dj_segfault points out, the shell can do most of this for you. Looks like you'll have to fall back on something external for lower-casing the string, though. For this you have many options, like the perl one-liners above, etc., but I think tr is probably the simplest.

# first, strip underscores
CLEAN=${STRING//_/}
# next, replace spaces with underscores
CLEAN=${CLEAN// /_}
# now, clean out anything that's not alphanumeric or an underscore
CLEAN=${CLEAN//[^a-zA-Z0-9_]/}
# finally, lowercase with TR
CLEAN=`echo -n $CLEAN | tr A-Z a-z`

The order here is somewhat important. We want to get rid of underscores, plus replace spaces with underscores, so we have to be sure to strip underscores first. By waiting to pass things to tr until the end, we know we have only alphanumeric and underscores, and we can be sure we have no spaces, so we don't have to worry about special characters being interpreted by the shell.

Bash can do this all on it's own, thank you very much. If you look at the section of the man page on Parameter Expansion, you'll see that that bash has built-in substitutions, substring, trim, rtrim, etc.

To eliminate all non-alphanumeric characters, do

CLEANSTRING=${STRING//[^a-zA-Z0-9]/}

That's Occam's razor. No need to launch another process.

Quick and dirty:

STRING=`echo 'dit /ZOU/ een test123' | perl -pe's/ //g;tr/[A-Z]/[a-z]/;s/[^a-zA-Z0-9]//g'`

You could run it through perl.

export CLEANSTRING=$(perl -e 'print join( q//, map { s/\\s+/_/g; lc } split /[^\\s\\w]+/, \$ENV{STRING} )')

I'm using ksh-style subshell here, I'm not totally sure that it works in bash.

That's the nice thing about shell, is that you can use perl, awk, sed, grep....

After a bit of looking around it seems tr is indeed the simplest way:

export CLEANSTRING="`echo -n "${STRING}" | tr -cd '[:alnum:] [:space:]' | tr '[:space:]' '-'  | tr '[:upper:]' '[:lower:]'`"

Occam's razor, I suppose.

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