%matplotlib line magic causes SyntaxError in Python script

早过忘川 提交于 2019-11-29 20:09:27

Line magics are only supported by the IPython command line. They cannot simply be used inside a script, because %something is not correct Python syntax.

If you want to do this from a script you have to get access to the IPython API and then call the run_line_magic function.

Instead of %matplotlib inline, you will have to do something like this in your script:

from IPython import get_ipython
get_ipython().run_line_magic('matplotlib', 'inline')

A similar approach is described in this answer, but it uses the deprecated magic function.

Note that the script still needs to run in IPython. Under vanilla Python the get_ipython function returns None and get_ipython().run_line_magic will raise an AttributeError.

Because line magics are only supported by the IPython command line not by Python cl, use: 'exec(%matplotlib inline)' instead of %matplotlib inline

Silvia07

The syntax '%' in %matplotlib inline is recognized by iPython (where it is set up to handle the magic methods), but not Python itself, which gives a SyntaxError. Here is given one solution.

If you include the following code at the top of your script, matplotlib will run inline when in an IPython environment (like jupyter, hydrogen atom plugin...), and it will still work if you launch the script directly via command line (matplotlib won't run inline, and the charts will open in a pop-ups as usual).

from IPython import get_ipython
ipy = get_ipython()
if ipy is not None:
    ipy.run_line_magic('matplotlib', 'inline')

There are several reasons as to why this wouldn't work.

It is possible that matplotlib is not properly installed. have you tried running:

conda install matplotlib

If that doesn't work, look at your %PATH% environment variable, does it contain your libraries and python paths?

Similar problem on github anaconda

This is the case you are using Julia:

The analogue of IPython's %matplotlib in Julia is to use the PyPlot package, which gives a Julia interface to Matplotlib including inline plots in IJulia notebooks. (The equivalent of numpy is already loaded by default in Julia.) Given PyPlot, the analogue of %matplotlib inline is using PyPlot, since PyPlot defaults to inline plots in IJulia.

Instead of %matplotlib inline,it is not a python script so we can write like this it will work from IPython import get_ipython get_ipython().run_line_magic('matplotlib', 'inline')

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!