Parse error: syntax error, unexpected '(', expecting ',' or ';' in

雨燕双飞 提交于 2019-11-26 09:53:04

问题


I am recieveing the following parse error:

Parse error: syntax error, unexpected \'(\', expecting \',\' or \';\' in H:\\Programs\\USBWebserver v8.5\\8.5\\root\\oopforum\\func\\register.class.php on line 7

which relates to the following line of code in my class:

private $random_name = rand(1000,9999).rand(1000,9999).rand(1000,9999).rand(1000,9999);

I can not see why this line of code would cause a parse error?

Here is some surrounding code:

class register{
    public $post_data = array();
        private $dbh;
        private $allowed_type = array(\'image/jpeg\',\'image/png\',\'image/gif\');
        private $random_name = rand(1000,9999).rand(1000,9999).rand(1000,9999).rand(1000,9999);
        private $path = \'img/thumb_/\'.$random_name. $_FILES[\'file\'][\'name\'];
        private $max_width = 4040;
        private $max_height = 4040;
        private $max_size = 5242880;
        private $temp_dir = $_FILES[\'file\'][\'tmp_name\'];
        private $image_type = $_FILES[\'file\'][\'type\'];
        private $image_size = $_FILES[\'file\'][\'size\'];
        private $image_name = $_FILES[\'file\'][\'name\'];
        private $image_dimensions = getimagesize($temp_dir);
        private $image_width = $image_dimensions[0]; // Image width
        private $image_height = $image_dimensions[1]; // Image height
        private $error = array();

        public function __construct($post_data, PDO $dbh){
        $this->post_data = array_map(\'trim\', $post_data);
        $this->dbh = $dbh;
        }
}

What is causing the parse error?


回答1:


You can't initialize member variables to anything that is not static, and you're trying to call a function.

From the manual:

This declaration may include an initialization, but this initialization must be a constant value--that is, it must be able to be evaluated at compile time and must not depend on run-time information in order to be evaluated.

The workaround is to set your variable in the constructor:

private $random_name;
public function __construct() { 
    $this->random_name = rand(1000,9999).rand(1000,9999).rand(1000,9999).rand(1000,9999);
}



回答2:


You can't do this:

private $image_dimensions = getimagesize($temp_dir);

Functions, variables, and anything else not static can't be called to set class variables.



来源:https://stackoverflow.com/questions/11313051/parse-error-syntax-error-unexpected-expecting-or-in

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!