PIL: Thumbnail and end up with a square image

妖精的绣舞 提交于 2019-11-29 19:25:36
Nadia Alramli

Paste the image into a transparent image with the right size as a background

from PIL import Image
size = (36, 36)
image = Image.open(data)
image.thumbnail(size, Image.ANTIALIAS)
background = Image.new('RGBA', size, (255, 255, 255, 0))
background.paste(
    image, (int((size[0] - image.size[0]) / 2), int((size[1] - image.size[1]) / 2))
)
background.save("output.png")

EDIT: fixed syntax error

Cesar Canassa

PIL already has a function to do exactly that:

from PIL import Image, ImageOps
thumb = ImageOps.fit(image, size, Image.ANTIALIAS)
from PIL import Image

import StringIO

def thumbnail_image():
    image = Image.open("image.png")
    image.thumbnail((300, 200))
    thumb_buffer = StringIO.StringIO()
    image.save(thumb_buffer, format=image.format)
    fp = open("thumbnail.png", "w")
    fp.write(thumb_buffer.getvalue())
    fp.close()
Khymeira

Or this, maybe... (forgive spaghetti)

from PIL import Image

def process_image(image, size):
    if image.size[0] > size[0] or image.size[1] > size[1]:
        #preserve original
        thumb = image.copy()
        thumb.thumbnail(size,Image.ANTIALIAS)
        img = thumb.copy()
    img_padded = Image.new("RGBA",size)
    img_padded.paste(image,(int((size[0]-image.size[0])/2),int((size[1]-image.size[1])/2)))
    return img_padded

you can wrap Nadia's answer in this function, which gives you control over size and background.

def make_square(im, min_size=36, fill_color=(255, 255, 255, 0)):
    x, y = im.size
    size = min(min_size, x, y)
    new_im = Image.new('RGBA', (size, size), fill_color)
    im.thumbnail((256, 256))
    new_im.paste(im, (int((x - size) / 2), int((y -size) / 2))
    return new_im
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