Unexpected $end in eval()'d code

问题

I hate to ask such a specific question, but I'm getting an error I can't figure out. This is in a cron job which runs on the hour. I'm creating an array of tasks, each of which has a date check which is supposed to be eval()'d.

$todo = array();
$todo[] = array( "date('z')%3 == 0", "Task 1" );
$todo[] = array( "date('N') == 1", "Task 2" );
foreach( $todo as $task )
{
    if( eval($task[0]) ) {
        echo $task[1];
    }
}

For some reason the eval() line is giving me this error. Note that I am getting this error for both tasks.

Parse error: syntax error, unexpected $end in /file.php(21) : eval()'d code on line 1

Any suggestions? I tried searching for this but couldn't find anything. Thank you.

回答1:

eval only accepts statements, not expressions. You need to convert your tests with:

if (eval("return $task[0];")) {

来源：https://stackoverflow.com/questions/6142550/unexpected-end-in-evald-code