leetcode1190

 1 class Solution:
 2     def reverseParentheses(self, s: str) -> str:
 3         stack = ['']
 4         for c in s:
 5             if c == '(':
 6                 stack.append('')
 7             elif c == ')':
 8                 add = stack.pop()[::-1]
 9                 stack[-1] += add
10             else:
11                 stack[-1] += c
12         return stack.pop()

参考：https://leetcode.com/problems/reverse-substrings-between-each-pair-of-parentheses/discuss/382775/Python3-straightforward-and-easiest-on-discussion

来源：https://www.cnblogs.com/asenyang/p/11524940.html