问题
In Java I might do this:
class MyClass {
private List<? extends MyInterface> list;
public void setList(List<MyImpl> l) { list = l; }
}
...assuming that (MyImpl implements MyInterface
) of course.
What is the analog for this in Scala, when using a Buffer
?
import java.lang.reflect._
import scala.collection.mutable._
class ScalaClass {
val list:Buffer[MyInterface] = null
def setList(l: Buffer[MyImpl]) = {
list = l
}
}
This (of course) doesn't compile - but how do I declare the list
variable in such a way that it does?
EDIT; I'm adding a bit more. The difference is obviously something to do with the fact that in Java, generics are never covariant in T, whereas in Scala they can be either covariant or not. For example, the Scala class List
is covariant in T (and necessarily immutable). Therefore the following will compile:
class ScalaClass {
val list:List[MyInterface] = null
def setList(l: List[MyImpl]) = {
list = l
}
}
I'm still struggling a bit with the compiler error:
Covariant type T occurs in contravariant position in ...
For example; this compiler error occurs in the class declaration:
class Wibble[+T] {
var some: T = _ //COMPILER ERROR HERE!
}
I'm going to ask a separate question...
回答1:
The direct analog to
import java.util.List;
List<? extends MyInterface> list;
is
import java.util.List
var list : List[_ <: MyInterface] = _;
Same deal with Buffer
To answer a comment you made earler, in Java type parameters are always invariant, not covariant.
回答2:
I'm not sure at all I understand your question (probably not enough coffee on my part) but it sounds like you're asking about generic classes. If that's not it, drop a comment or add more information to your question & I'll check back later & edit my answer.
来源:https://stackoverflow.com/questions/663032/generic-wildcards-in-variable-declarations-in-scala