Standard Deviation in R Seems to be Returning the Wrong Answer - Am I Doing Something Wrong?

问题

A simple example of calculating standard dev:

d <- c(2,4,4,4,5,5,7,9)
sd(d)

yields

[1] 2.13809

but when done by hand, the answer is 2. What am I missing here?

回答1:

Try this

R> sd(c(2,4,4,4,5,5,7,9)) * sqrt(7/8)
[1] 2
R> 

and see the rest of the Wikipedia article for the discussion about estimation of standard deviations. Using the formula employed 'by hand' leads to a biased estimate, hence the correction of sqrt((N-1)/N). Here is a key quote:

The term standard deviation of the sample is used for the uncorrected estimator (using N) while the term sample standard deviation is used for the corrected estimator (using N − 1). The denominator N − 1 is the number of degrees of freedom in the vector of residuals, .

回答2:

Looks like R is assuming (n-1) in the denominator, not n.

回答3:

When I want the population variance or standard deviation (n as denominator), I define these two vectorized functions.

  pop.var <- function(x) var(x) * (length(x)-1) / length(x)

  pop.sd <- function(x) sqrt(pop.var(x))

BTW, Khan Academy has a good discussion of population and sample standard deviation here.

回答4:

Note that running the command

?sd 

in R Studio displays the help page for the function. In the details section it states

Like var this uses denominator n - 1.

来源：https://stackoverflow.com/questions/6457755/standard-deviation-in-r-seems-to-be-returning-the-wrong-answer-am-i-doing-some