Python RegExp global flag

问题

Is there a flag or some special key in python to use pattern multiple times. I used to test http://gskinner.com/RegExr/ my RegExp, it worked correctly in it. But when testing in correct enviorment match only returns None.

import re
pattern = r"(?P<date>--\d\d-\w+:\d\d)[ \t]+(?P<user>\w+)[ \t]+(?P<method>[\w ]+)[\" ]*    (?P<file>[\w\\:\.]+)@@(?P<version>[\w\\]+)[\" ]*(?P<labels>[\(\w, \.\)]+){0,1}[\s \"]*(?P<comment>[\w \.-]+){0,1}[\"]"
base = """
--02-21T11:22  user3   create version "W:\foo\bar\fooz.bat@@\main\1" (label1, label2,   label3, label22, label33, ...)

"merge in new bat-based fooz installer"

--02-21T11:22  user1   create version "W:\foo\bar\fooz.bat@@\main\0"

--02-21T11:22  user2   create branch "W:\foo\bar\fooz.bat@@\main\"

"merge in new bat-based fooz installer"

--02-13T11:22  user1   create version     "W:\foo\bar\fooz.bat@@\main\1"

  "Made to use new fooz.bat"

"""
r = re.match(pattern, base)
print(r)

回答1:

re.match tries to match the pattern at the start of the string. You are looking for re.search, re.findall or re.finditer

来源：https://stackoverflow.com/questions/11686516/python-regexp-global-flag