问题
I am using RestTemplate to make an HTTP call to our service which returns a simple JSON response. I don't need to parse that JSON at all. I just need to return whatever I am getting back from that service.
So I am mapping that to String.class and returning the actual JSON response as a string.
RestTemplate restTemplate = new RestTemplate();
String response = restTemplate.getForObject(url, String.class);
return response;
Now the question is -
I am trying to extract HTTP Status codes after hitting the URL. How can I extract HTTP Status code from the above code? Do I need to make any change into that in the way I doing it currently?
Update:-
This is what I have tried and I am able to get the response back and status code as well. But do I always need to set HttpHeaders and Entity object like below I am doing it?
RestTemplate restTemplate = new RestTemplate();
//and do I need this JSON media type for my use case?
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
//set my entity
HttpEntity<Object> entity = new HttpEntity<Object>(headers);
ResponseEntity<String> out = restTemplate.exchange(url, HttpMethod.GET, entity, String.class);
System.out.println(out.getBody());
System.out.println(out.getStatusCode());
Couple of question - Do I need to have MediaType.APPLICATION_JSON as I am just making a call to url which returns a response back, it can return either JSON or XML or simple string.
回答1:
Use the RestTemplate#exchange(..) methods that return a ResponseEntity. This gives you access to the status line and headers (and the body obviously).
回答2:
If you don´t want to leave the nice abstraction around RestTemplate.get/postForObject... methods behind like me and dislike to fiddle around with the boilerplate stuff needed when using RestTemplate.exchange... (Request- and ResponseEntity, HttpHeaders, etc), there´s another option to gain access to the HttpStatus codes.
Just surround the usual RestTemplate.get/postForObject... with a try/catch for org.springframework.web.client.HttpClientErrorException and org.springframework.web.client.HttpServerErrorException, like in this example:
try {
return restTemplate.postForObject("http://your.url.here", "YourRequestObjectForPostBodyHere", YourResponse.class);
} catch (HttpClientErrorException | HttpServerErrorException httpClientOrServerExc) {
if(HttpStatus.NOT_FOUND.equals(httpClientOrServerExc.getStatusCode())) {
// your handling of "NOT FOUND" here
// e.g. throw new RuntimeException("Your Error Message here", httpClientOrServerExc);
}
else {
// your handling of other errors here
}
The org.springframework.web.client.HttpServerErrorException is added here for the errors with a 50x.
Now you´re able to simple react to all the StatusCodes you want - except the appropriate one, that matches your HTTP method - like GET and 200, which won´t be handled as exception, as it is the matching one. But this should be straight forward, if you´re implementing/consuming RESTful services :)
回答3:
private RestTemplate restTemplate = new RestTemplate();
ResponseEntity<String> response = restTemplate.exchange(url,HttpMethod.GET, requestEntity,String.class);
response contains 'body', 'headers' and 'statusCode'
to get statusCode : response.getStatusCode();
回答4:
If you want all the HTTPStatus from a RestTemplate including 4XX and 5XX, you will have to provide an ResponseErrorHandler to the restTemplate, since the default handler will throw an exception in case of 4XX or 5XX
We could do something like that :
RestTemplate restTemplate = new RestTemplate();
restTemplate.setErrorHandler(new DefaultResponseErrorHandler() {
@Override
public boolean hasError(HttpStatus statusCode) {
return false;
}
});
ResponseEntity<YourResponse> responseEntity =
restTemplate.getForEntity("http://your.url.here", YourResponse.class);
assertThat(responseEntity.getStatusCode()).isEqualTo(HttpStatus.XXXX);
回答5:
There can be some slightly trickier use cases someone might fall in (as I did). Consider the following:
Supporting a Page object in order to use it with RestTemplate and ParameterizedTypeReference:
RestPageResponse:
import java.util.ArrayList;
import java.util.List;
import org.springframework.data.domain.PageImpl;
import org.springframework.data.domain.Pageable;
public class RestResponsePage<T> extends PageImpl<T>{
private static final long serialVersionUID = 3248189030448292002L;
public RestResponsePage(List<T> content, Pageable pageable, long total) {
super(content, pageable, total);
}
public RestResponsePage(List<T> content) {
super(content);
}
public RestResponsePage() {
super(new ArrayList<T>());
}
}
Using ParameterizedTypeReference will yield the following:
ParameterizedTypeReference<RestResponsePage<MyObject>> responseType =
new ParameterizedTypeReference<RestResponsePage<MyObject>>() {};
HttpEntity<RestResponsePage<MyObject>> response = restTemplate.exchange(oauthUrl, HttpMethod.GET, entity, responseType);
Calling #exchange:
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<?> entity = new HttpEntity<>(headers);
response = restTemplate.exchange("localhost:8080/example", HttpMethod.GET, entity, responseType);
Now here is the "tricky" part.
Trying to call exchange's getStatusCode will be impossible because the compiler, unfortunately, will be unaware of the "intended" type of response.
That is because generics are implemented via type erasure which removes all information regarding generic types during compilation (read more - source)
((ResponseEntity<RestResponsePage<MyObject>>) response).getStatusCode()
In this case, you have to explicitly cast the variable to the desired Class to get the statusCode (and/or other attributes)!
回答6:
exchange(...) works but if you want less code, you can use
org.springframework.boot.test.web.client.TestRestTemplate.getForEntity(...)
which returns an Entity containing StatusCode. Change your example code to this:
RestTemplate restTemplate = new RestTemplate();
ResponseEntity<String> response = restTemplate.getForEntity(url, String.class);
HttpStatus statusCode = response.getStatusCode();
To test it you can use this snippet from my unit test:
ResponseEntity<String> response = restTemplate.getForEntity(url, String.class);
assertResponseHeaderIsCorrect(response, HttpStatus.OK);
/**
* Test the basics of the response, non-null, status expected, etc...
*/
private void assertResponseHeaderIsCorrect(ResponseEntity<String> response, HttpStatus expectedStatus) {
assertThat(response).isNotNull();
assertThat(response.getHeaders().getContentType()).isEqualTo(MediaType.APPLICATION_JSON_UTF8);
assertThat(response.getStatusCode()).isEqualTo(expectedStatus);
}
回答7:
Putting this much of code is enough for me
HttpStatus statusCode = ((ResponseEntity<Object>) responseOfEsoft).getStatusCode();
来源：https://stackoverflow.com/questions/23205213/how-to-extract-http-status-code-from-the-resttemplate-call-to-a-url