给定一个整数 n,生成所有由 1 ... n 为节点所组成的二叉搜索树。
示例:
输入: 3
输出:
[
[1,null,3,2],
[3,2,null,1],
[3,1,null,null,2],
[2,1,3],
[1,null,2,null,3]
]
解释:
以上的输出对应以下 5 种不同结构的二叉搜索树:
1 3 3 2 1
\ / / / \ \
3 2 1 1 3 2
/ / \ \
2 1 2 3
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/unique-binary-search-trees-ii
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<TreeNode*> generateTrees(int n)
{
if (n == 0)
return {};
return helper(1, n);
}
vector<TreeNode*> helper(int left, int right)
{
vector<TreeNode*> res;
if(left > right)
{
res.push_back(NULL);
return res;
}
for(int i = left; i <= right; i++)
{
vector<TreeNode*> leftTree = helper(left, i-1);
vector<TreeNode*> rightTree = helper(i+1, right);
for(auto tree1 : leftTree)
{
for(auto tree2 : rightTree)
{
TreeNode* root = new TreeNode(i);
root->left = tree1;
root->right = tree2;
res.push_back(root);
}
}
}
return res;
}
};
来源:https://blog.csdn.net/weixin_41791402/article/details/100064595