Generating permutations of a list in NetLogo

◇◆丶佛笑我妖孽 提交于 2019-11-29 11:30:36

If you don't mind a recursive solution, you could do this:

to-report permutations [#lst] ;Return all permutations of `lst`
  let n length #lst
  if (n = 0) [report #lst]
  if (n = 1) [report (list #lst)]
  if (n = 2) [report (list #lst reverse #lst)]
  let result []
  let idxs n-values n [?]
  foreach idxs [
    let xi item ? #lst
    foreach (permutations remove-item ? #lst) [
      set result lput (fput xi ?) result
    ]
  ]
  report result
end

Edit: Updated syntax in response to comment.

to-report permutations [#lst] ;Return all permutations of `lst`
  let n length #lst
  if (n = 0) [report #lst]
  if (n = 1) [report (list #lst)]
  if (n = 2) [report (list #lst reverse #lst)]
  let result []
  let idxs range n
  foreach idxs [? ->
    let xi item ? #lst
    foreach (permutations remove-item ? #lst) [?? ->
      set result lput (fput xi ??) result
    ]
  ]
  report result
end
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