Collection type generated by for with yield

问题

When I evaluate a for in Scala, I get an immutable IndexedSeq (a collection with array-like performance characteristics, such as efficient random access):

scala> val s = for (i <- 0 to 9) yield math.random + i
s: scala.collection.immutable.IndexedSeq[Double] = Vector(0.6127056766832756, 1.7137598183155291, ...

Does a for with a yield always return an IndexedSeq, or can it also return some other type of collection class (a LinearSeq, for example)? If it can also return something else, then what determines the return type, and how can I influence it?

I'm using Scala 2.8.0.RC3.

回答1:

Thanks michael.kebe for your comment.

This explains how for is translated to operations with map, flatMap, filter and foreach. So my example:

val s = for (i <- 0 to 9) yield math.random + i

is translated to something like this (I'm not sure if it's translated to map or flatMap in this case):

val s = (0 to 9) map { math.random + _ }

The result type of operations like map on collections depends on the collection you call it on. The type of 0 to 9 is a Range.Inclusive:

scala> val d = 0 to 9
d: scala.collection.immutable.Range.Inclusive with scala.collection.immutable.Range.ByOne = Range(0, 1, 2, 3, 4, 5, 6, 7, 8, 9)

The result of the map operation on that is an IndexedSeq (because of the builder stuff inside the collections library).

So, to answer my question: the result of a for (...) yield ... depends on what type is inside the parantheses. If I want a List as the result, I could do this:

scala> val s = for (i <- List.range(0, 9)) yield math.random + i
s: List[Double] = List(0.05778968639862214, 1.6758775042995566, ...

回答2:

You can always transform a range to a list using toList:

> val s = for (i <- (0 to 9).toList) yield math.random + i
> s  : List[Double]

来源：https://stackoverflow.com/questions/2947896/collection-type-generated-by-for-with-yield