How to get application path

Question

i am using

string path = AppDomain.CurrentDomain.BaseDirectory; to get my application path ,but this gives something like

C:\Projects\XYZ\ABC\bin\Debug

i don't want bin\Debug .Is there any way to achieve this ?

Answer 1

The AppDomain.CurrentDomain.BaseDirectory property gets the base directory that the assembly resolver uses to probe for assemblies.

So it's functioning 100% as it should. If you were to build your application, cut and paste it somewhere else in another folder or drive. Those changes would be reflected in this property.

Also, you mentioned that you do not want this part bin\Debug, so you want what's before that? Please be specific.

Answer 2

If you want to figure out your application executable path (as I understood):

string path = Application.ExecutablePath;

Answer 3

You are running the program within IDE, and that's the reason why you get this kind of path. Try to build the app and run it outside IDE - you'll see that the method works correctly.

Edit: what you obtain is because IDE runs debug build of your app which is located in $PROJECT_DIR\bin\Debug.

Answer 4

string LPath;
string Location = AppDomain.CurrentDomain.BaseDirectory + "Reports\\rptEmployInfoStat.rpt";
int index;
index = Location.IndexOf("bin");
if (index > 0)
{
     LPath = Location.Remove(index, 10);
}
else
{
     LPath = Location;
}
rd.Load(@LPath);

Answer 5

To be honest, this is not the best pratice but this will give what you want:

string dir = System.IO.Directory.GetCurrentDirectory().Replace("\\bin\\Debug", "");

Answer 6

I am using this:

String appSettingsPath = Directory.GetCurrentDirectory();

        if (!File.Exists(Path.Combine(appSettingsPath, "appsettings.json")))
            appSettingsPath = Path.GetDirectoryName(Path.GetDirectoryName(appSettingsPath));

Answer 7

to get what you want:

var enviroment = System.Environment.CurrentDirectory;
string projectDirectory = Directory.GetParent(enviroment).Parent.FullName;