function name($param, $line = __LINE__, $file = __FILE__) {};

有些话、适合烂在心里 提交于 2019-11-29 10:38:22
Wrikken

The only way would be using debug_backtrace(), but as the name says: it is for debugging. Your code should not attach any meaning or functionality in production based on where/when it's called.

Tom Haigh

Doing what you suggest doesn't seem to work.

You can do it like this, but I'm not sure why you want to do it and that there isn't a better approach to what you are trying to achieve - see Wrikken's answer.

<?php

function test() {
    $backtrace = debug_backtrace();
    $last = $backtrace[0];
    echo "{$last['function']}() called from {$last['file']} line {$last['line']}\r\n"; 
}



test();

It's so late but maybe can be useful, you can use get_called_class(), for the name of class who is called, and do not pass like a parameter insted of CLASS.

if you want to use this information in some kind of error message, there is a function trigger_error() which will raise PHP native error, so, therefore, it will be shown in usual PHP manner - with filename, line number and supplied text.

Most neat feature of this function is behaving according to current error handling settings:

ini_set('display_errors',1);
trigger_error("Horrible bug found!");

will print out directly to screen an error message like this:

Notice: Horrible bug found! in /path/file.php on line 2

very handy for developing
while this code

ini_set('display_errors',0);
ini_set('log_errors',1);
trigger_error("Horrible bug found!");

will be put into error log for the future reference
obligatory for the production

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