This might be a weird requirement but it's what I've run into. I Googled but yield nothing.
I'm coding an application who's using a lot of constant attributes / values recorded in an XML file (they'll not change so a static file), things work fine until I generated an egg file for it.
When the logic reaches the XML accessing part, I got one complaint like this: /home/Workspace/my_proj/dist/mps-1.2.0_M2-py2.6.egg/mps/par/client/syntax/syntax.xml
Actually I've bundled the XML file in the path above but seems Python doesn't know how to access it.
The code to access the XML is as...
file_handler = open(path_to_the_file)
lines = file_handler.read().splitlines()
Any idea?
egg files are zipfiles, so you must access "stuff" inside them with the zipfile module of the Python standard libraries, not with the built-in open function!
If you want to access the contents inside the .egg file you can simply rename it and change extension from .egg to .zip and than unzip it. Which will create a folder and the contents will be same as they were when it was a .egg file
for example brewer2mpl-1.4.1-py3.6.egg
After Renaming brewer2mpl-1.4.1-py3.6.zip
Now if we open it, it'll get easily unzipped and the content will be put in a folder with same name in the same directory. (tested on macOS Sierra)
Access file from inside egg file
Yes, It is possible to read the files from inside egg file.
Egg file: mps-1.2.0_M2-py2.6.egg structure for module level example:
In driverfile.py:
import xml.etree.ElementTree
import mps.par.client as syntaxpath
import os
path = os.path.dirname(syntaxpath.__file__)
element = xml.etree.ElementTree.parse(path+'\\syntax\\syntax.xml').getroot()
print(element)
Read xml file from inside an eggfile:
PYTHONPATH=mps-1.2.0_M2-py2.6.egg python driverfile.py
just use unzip file.egg this should be enough.
i think by default eggs packing file under python won't add your xml inside to the pack
来源：https://stackoverflow.com/questions/3655352/how-to-access-files-inside-a-python-egg-file