How to get a particular date format ('dd-MMM-yyyy') in SELECT query SQL Server 2008 R2

不打扰是莪最后的温柔 提交于 2019-11-29 07:30:33

问题


I am using CONVERT(data_type(length),expression,style) function to change the format of a date in a SELECT query.

Declare @dt nvarchar(20)

Select @dt = Convert(nvarchar(20), SalesDate, 113) FROM SalesTable

The format I need is 'dd-MMM-yyyy' (eg. '05-Jul-2013') but I could not find the proper style number (eg. 113) for this particular format. Can any one help me with that please?


回答1:


Try this:

Declare @dt NVARCHAR(20)

Select 
    @dt = REPLACE(CONVERT(CHAR(15), SalesDate, 106),' ',' - ') 
FROM SalesTable



回答2:


select CONVERT(NVARCHAR, SYSDATETIME(), 106) AS [DD-MON-YYYY]

or else

select REPLACE(CONVERT(NVARCHAR,GETDATE(), 106), ' ', '-')

both works fine




回答3:


It doesn't look like DD-MMM-YYYY is supported by default (at least, with dash as separator). However, using the AS clause, you should be able to do something like:

SELECT CONVERT(VARCHAR(11), SYSDATETIME(), 106) AS [DD-MON-YYYY]

See here: http://www.sql-server-helper.com/sql-server-2008/sql-server-2008-date-format.aspx




回答4:


I Think this is the best way to do it.

REPLACE(CONVERT(NVARCHAR,CAST(WeekEnding AS DATETIME), 106), ' ', '-')

Because you do not have to use varchar(11) or varchar(10) that can make problem in future.




回答5:


SELECT Convert(varchar(10),CONVERT(date,'columnname',105),105) as "end";

OR

SELECT CONVERT(VARCHAR(10), CAST(event_enddate AS DATE), 105) AS [end];

will return the particular date in the format of 'dd-mm-yyyy'

The result would be like this..

04-07-2016



回答6:


select convert(varchar(11), transfer_date, 106)

got me my desired result of date formatted as 07 Mar 2018

My column transfer_date is a datetime type column and I am using SQL Server 2017 on azure



来源:https://stackoverflow.com/questions/18202260/how-to-get-a-particular-date-format-dd-mmm-yyyy-in-select-query-sql-server-2

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