Select second most minimum value in Oracle

Question

I need to write a query that selects a minimum value and it's second most minimum value from a list of integers.

Grabbing the smallest value is obvious:

select min(value) from table;

But the second smallest is not so obvious.

For the record, this list of integers is not sequential -- the min can be 1000, and the second most min can be 10000.

Answer 1

Use an analytic function

SELECT value
  FROM (SELECT value,
               dense_rank() over (order by value asc) rnk
          FROM table)
 WHERE rnk = 2

The analytic functions RANK, DENSE_RANK, and ROW_NUMBER are identical except for how they handle ties. RANK uses a sports-style process of breaking ties so if two rows tie for a rank of 1, the next row has a rank of 3. DENSE_RANK gives both of the rows tied for first place a rank of 1 and then assigns the next row a rank of 2. ROW_NUMBER arbitrarily breaks the tie and gives one of the two rows with the lowest value a rank of 1 and the other a rank of 2.

Answer 2

select 
  value
from
  (select 
    value, 
    dense_rank() over (order by value) rank
  from 
    table)
where
  rank = 2

Advantage: You can get the third value just as easy, or the bottom 10 rows (rank <= 10).

Note that the performance of this query will benefit from a proper index on 'value'.

Answer 3

SELECT MIN(value)
FROM TABLE
WHERE Value > (SELECT MIN(value) FROM TABLE)