问题
I would like to use gsub to replace every occurrence of a backslash in a string with 2 backslashes.
Currently, what I have I tried is gsub(\"\\\\\\\\\", \"\\\\\", x). This doesn\'t seem to work though. However, if I change the expression to instead replace each backslash with \"a\", it works fine.
> gsub(\"\\\\\\\\\", \"\\\\\", \"\\\\\")
[1] \"\"
> gsub(\"\\\\\\\\\", \"a\", \"\\\\\")
[1] \"a\"
> gsub(\"\\\\\\\\\", \"\\\\\\\\\", \"\\\\\")
[1] \"\\\\\"
The last character is only a single backslash; R just prints 2 because it prints escaped characters with the backslash. Using nchar confirms that the length is 1.
What causes this functionality? The second argument to gsub isn\'t a regular expression, so having 4 backslashes in the string literal should be converted to a character with 2 backslashes. It makes even less sense that the first gsub call above returns an empty string.
回答1:
Here's what you need:
gsub("\\\\", "\\\\\\\\", "\\")
[1] "\\\\"
The reason that you need four backslashes to represent one literal backslash is that "\" is an escape character in both R strings and for the regex engine to which you're ultimately passing your patterns. If you were talking directly to the regex engine, you'd use "\\" to indicate a literal backslash. But in order to get R to pass "\\" on to the regex engine, you need to type "\\\\".
(If you are just wanting to double backslashes, you might want to use this instead):
gsub("\\", "\\\\", "\\", fixed=TRUE)
[1] "\\\\"
来源：https://stackoverflow.com/questions/27491986/r-gsub-replacing-backslashes