Get most recent date from an array of dates

问题

I have the array of dates below

array(5) { 
    [0]=> string(19) \"2012-06-11 08:30:49\" 
    [1]=> string(19) \"2012-06-07 08:03:54\" 
    [2]=> string(19) \"2012-05-26 23:04:04\" 
    [3]=> string(19) \"2012-05-27 08:30:00\" 
    [4]=> string(19) \"2012-06-08 08:30:55\" 
}

and would like to know the most recent date as in: the closest to today\'s date.

How can I do that?

回答1:

Do a loop, convert the values to date, and store the most recent, in a var.

$mostRecent= 0;
foreach($dates as $date){
  $curDate = strtotime($date);
  if ($curDate > $mostRecent) {
     $mostRecent = $curDate;
  }
}

something like that... you get the idea If you want most recent BEFORE today :

$mostRecent= 0;
$now = time();
foreach($dates as $date){
  $curDate = strtotime($date);
  if ($curDate > $mostRecent && $curDate < $now) {
     $mostRecent = $curDate;
  }
}

回答2:

Use max(), array_map(), and strtotime().

$max = max(array_map('strtotime', $arr));
echo date('Y-m-j H:i:s', $max); // 2012-06-11 08:30:49

回答3:

Sort the array by date, and then get the front value of the array.

$dates = array(5) { /** omitted to keep code compact */ }
$dates = array_combine($dates, array_map('strtotime', $dates));
arsort($dates);
echo $dates[0];

回答4:

$dates = [
    "2012-06-11 08:30:49" 
    ,"2012-06-07 08:03:54" 
    ,"2012-05-26 23:04:04" 
    ,"2012-05-27 08:30:00" 
    ,"2012-06-08 08:30:55" 
];
echo date("Y-m-d g:i:s",max(array_map('strtotime',$dates)));

回答5:

Thats my variant. It works with date in future.

$Dates = array( 
    "2012-06-11 08:30:49", 
    "2012-06-07 08:03:54", 
    "2012-05-26 23:04:04",
    "2012-05-27 08:30:00",
    "2012-06-08 08:30:55",
    "2012-06-12 07:45:45"
);
$CloseDate = array();
$TimeNow = time();
foreach ($Dates as $Date) {
  $DateToCompare = strtotime($Date);
  $Diff = $TimeNow - $DateToCompare;
  if ($Diff < 0) $Diff *= -1;
  if (count($CloseDate) == 0) {
    $CloseDate['Date'] = $Date;
    $CloseDate['Diff'] = $Diff;
    continue;
  }
  if ($Diff < $CloseDate['Diff']) {
    $CloseDate['Date'] = $Date;
    $CloseDate['Diff'] = $Diff;
  }
}

var_dump($CloseDate);

回答6:

I believe, following is the shortest code to find the recent date. you can alter it to find the index of the recent date or to find the recent in future or past.

$Dates = array( 
"2012-06-11 08:30:49", 
"2012-06-07 08:03:54", 
"2012-05-26 23:04:04",
"2012-05-27 08:30:00",
"2012-06-08 08:30:55",
"2012-06-22 07:45:45"
);

$close_date = current($Dates);
foreach($Dates as $date)
    if( abs(strtotime('now') - strtotime($date)) < abs(strtotime('now') - strtotime($close_date)))
        $close_date = $date;

echo $close_date;

回答7:

Here is my suggestion:

$most_recent = 0;

foreach($array as $key => $date){
    if( strtotime($date) < strtotime('now') && strtotime($date) > strtotime($array[$most_recent]) ){
        $most_recent = $key;
    }
}

print $array[$most_recent]; //prints most recent day

回答8:

$arrayy = array(
    "2012-06-11 08:30:49","2012-06-07 08:03:54","2012-05-26 23:04:04",
    "2012-05-27 08:30:00","2012-06-08 08:30:55" 
);

function getMostRecent($array){
    $current = date("Y-m-d h:i:s");
    $diff1 = NULL;
    $recent = NULL;
    foreach($array as $date){
        if($diff = strcmp($current,$date)){
            if($diff1 == NULL){
                $diff1 = $diff;
                $recent = $date;
            }
            else{
                if($diff < $diff1){
                    $diff1 = $diff;
                    $recent = $date;
                }
            }
        }
    }
    return $recent;
}

回答9:

Try this:

public function getLargerDate(array $datas) {
    $newDates = array();
    foreach($datas as $data){
        $newDates[strtotime($data)] = $data;
    }
    return $newDates[max(array_keys($newDates))];
}

回答10:

Try this works 100%

function getRecentDate($date_list,$curDate){
$curDate = strtotime($curDate); 
    $mostRecent = array();
    foreach($date_list as $date){                                             
       $diff = strtotime($date)-$curDate;
       if($diff>0){
        $mostRecent[$diff] = $date;
       }
    }   
    if(!empty($mostRecent)){
        ksort($mostRecent);            
        $mostRecent_key = key($mostRecent);
        if($mostRecent_key){
            return $mostRecent[$mostRecent_key];
        }
    }else{
        return false;
    }
}
$date_list = array('15-05-2015','14-01-2015','18-03-2015','20-10-2016','12-12-2014','12-12-2015');
$curDate = '14-01-2015';    
$get_recent = getRecentDate($date_list,$curDate);
if($get_recent){
    echo $get_recent;
}else{
    echo 'No recent date exists';
}

回答11:

$DatesList = array( '2015-05-19', '2015-09-17', '2015-09-24', '2015-10-02', '2015-10-23', '2015-11-12', '2015-12-25' );

$counter = 0; 
$currentDate = date("Y-m-d");
foreach ($DatesList as $dates)
{
    if($dates >= $currentDate)
    {
        $storeDates[$counter] = $dates;
        $counter++;
    }
}
$closestDate = current($storeDates);
echo $closestDate;

来源：https://stackoverflow.com/questions/11012891/get-most-recent-date-from-an-array-of-dates