Is there a bash command for converting an entire directory to HAML from HTML?

余生长醉 提交于 2019-11-29 03:42:27

问题


I'm looking to convert an entire directory of HTML to HAML so that the files have the same name but with a new extension.

html2haml file.html.erb file.haml

Can I run a loop so that I can convert all these files all at once so that the name is the same just the extension is changed?

My files:

continue_login.html.erb
expired_trial.html.erb
expired_trial.mobile.erb
login.html.erb
login.mobile.erb
recover_password.html.erb
signup.html.erb
trial_expires_soon.html.erb
trial_expires_soon.mobile.erb

回答1:


It's not sexy but it's working:

for file in $(find . -type f -name \*.html.erb); do
  html2haml -e ${file} "$(dirname ${file})/$(basename ${file} .erb).haml";
done

(Pay attention to the -e flag of html2haml it parses the ERb tags.)




回答2:


You could do something like this:

for f in *.html.erb; do html2haml $f ${f/\.html\.erb/.haml}; done

Edit: If you need to look for template files recursively and you're using bash 4.x, then you can use globstar:

shopt -s globstar
for f in **/*.html.erb; do html2haml $f ${f/\.html\.erb/.haml}; done



回答3:


From https://gist.github.com/pho3nixf1re/1281382 looks like it does a whole directory tree:

#!/bin/bash
if [ -z "$1" ]; then
  wdir="."
else
  wdir=$1
fi

for f in $( find . -name '*.erb' ); do
  out="${f%.erb}.haml"
  if [ -e $out ]; then
    echo "skipping $out; already exists"
    # rm $f
  else
    echo "hamlifying $f"
    html2haml $f > $out
    # rm $f
  fi
done


来源:https://stackoverflow.com/questions/9398776/is-there-a-bash-command-for-converting-an-entire-directory-to-haml-from-html

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!