How to run os.mkdir() with -p option in Python?

Question

I want to run mkdir command as:

mkdir -p directory_name

What's the method to do that in Python?

os.mkdir(directory_name [, -p]) didn't work for me.

Answer 1

You can try this:

# top of the file
import os
import errno

# the actual code
try:
    os.makedirs(directory_name)
except OSError as exc: 
    if exc.errno == errno.EEXIST and os.path.isdir(directory_name):
        pass

Answer 2

Something like this:

if not os.path.exists(directory_name):
    os.makedirs(directory_name)

UPD: as it is said in a comments you need to check for exception for thread safety

try:
    os.makedirs(directory_name)
except OSError as err:
    if err.errno!=17:
        raise

Answer 3

According to the documentation, you can now use this since python 3.2

os.makedirs("/directory/to/make", exist_ok=True)

and it will not throw an error when the directory exists.

Answer 4

If you're using pathlib, use Path.mkdir(parents=True, exist_ok=True)

from pathlib import Path

new_directory = Path('./some/nested/directory')
new_directory.mkdir(parents=True, exist_ok=True)

parents=True creates parent directories as needed

exist_ok=True tells mkdir() to not error if the directory already exists

See the pathlib.Path.mkdir() docs.

Answer 5

how about this os.system('mkdir -p %s' % directory_name )