Specified initialization vector (IV) does not match the block size for this algorithm

问题

I am working on a base encryption method. I am using RijndaelManaged. I got this code from somewhere a long time ago, but can't remember where.

I had my code working before, but something changed and I cannot quite figure it out.

When I run my code, I get the following error;

Specified initialization vector (IV) does not match the block size for this algorithm.

Here is my code:

string textToEncrypt = "TEST STRING";

int keySize = 256;
string hashAlgorithm = "SHA1";
string passPhrase = "AH!PSB0%FGHR$";
string saltValue = "LRT%YUR#VBNL@1";
string initVector = "HR$2pIjHR$2pIj";

byte[] initVectorBytes = Encoding.ASCII.GetBytes(initVector);
byte[] saltValueBytes = Encoding.ASCII.GetBytes(saltValue);

byte[] plainTextBytes = Encoding.UTF8.GetBytes(textToEncrypt);

var password = new PasswordDeriveBytes(passPhrase, saltValueBytes, hashAlgorithm, 2);

byte[] keyBytes = password.GetBytes(keySize / 8);

RijndaelManaged symmetricKey = new RijndaelManaged();

symmetricKey.Mode = CipherMode.CBC;

ICryptoTransform encryptor = symmetricKey.CreateEncryptor(keyBytes,initVectorBytes);

MemoryStream memoryStream = new MemoryStream();

var cryptoStream = new CryptoStream(memoryStream,encryptor,CryptoStreamMode.Write);
cryptoStream.Write(plainTextBytes, 0, plainTextBytes.Length);

cryptoStream.FlushFinalBlock();

byte[] cipherTextBytes = memoryStream.ToArray();

memoryStream.Close();
cryptoStream.Close();

string cipherText = Convert.ToBase64String(cipherTextBytes);

Any help will be appreciated.

回答1:

The problem is your initialization vector size needs to be 16 bytes.

Your initial vector size is 14 bytes.

You will need to increase the size of your initial vector by 2 bytes and your code will work.

Example:

string initVector = "HR$2pIjHR$2pIj12";

You will then get the output with your current code and the example IV (initialization vector) size provided:

hAC8hMf3N5Zb/DZhFKi6Sg==

This article provides a good explanation on what the initialization vector is.

http://en.wikipedia.org/wiki/Initialization_vector

回答2:

You should be able to check how many bytes the IV needs to be using:

algorithm.BlockSize / 8

BlockSize is in bits, so 128 bits / 8 gives 16 bytes of ASCII, and you may also find Rfc2898DeriveBytes a useful class for producing keys.

algorithm.IV = rfc2898DeriveBytesForIV.GetBytes(algorithm.BlockSize / 8);

Hope it helps.

来源：https://stackoverflow.com/questions/944833/specified-initialization-vector-iv-does-not-match-the-block-size-for-this-algo

标签

encryption

rijndaelmanaged

rijndael