How to exit a child process and return its status from execvp()?

老子叫甜甜 提交于 2019-11-29 01:25:46
Nathan Fellman

You need to use waitpid(3) or wait(1) in the parent code to wait for the child to exit and get the error message.

The syntax is:

pid_t waitpid(pid_t pid, int *status, int options);

or

pid_t wait(int *status);

status contains the exit status. Look at the man pages to see you how to parse it.


Note that you can't do this from the child process. Once you call execvp the child process dies (for all practical purposes) and is replaced by the exec'd process. The only way you can reach exit(0) there is if execvp itself fails, but then the failure isn't because the new program ended. It's because it never ran to begin with.

Edit: the child process doesn't really die. The PID and environment remain unchanged, but the entire code and data are replaced with the exec'd process. You can count on not returning to the original child process, unless exec fails.

From your question it's a little hard to figure out what you're asking. So I'll try to cover a couple of the related issues:

  • execvp() either does not return (on success), or it returns an error. Meaning your child code only need handle error conditions. Your child code should capture the result of execvp() and use that value in exit() as you suggested. Your child code should never return 0, since the only success means that the execvp worked and that processs will return 0 (or not).
  • The parent can obtain child info from waitpid() about it's exit status. There are several macros defined to pull info from the returned status parameter. Notable for your purpose are WIFEXITED to tell you if the child exited "normally", and WEXITSTATUS to get the child's status as passed to exit(). See the waitpid man page for other macros.
Bastien Léonard

Use wait() or waitpid() in the parent process. An example here: Return code when OS kills your process.

Also, when a child dies the SIGCHLD signal is sent to the parent process.

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