How can i pass data to django layouts (like 'base.html') without having to provide it through every view?

问题

I am trying to pass the data to layout 'base.html'. I am currently doing it by storing the data in request.session and accessing it in 'base.html' through request object.

Is there any way to pass the data to 'base.html' without having to pass the data from every views?

回答1:

Use a context processor, which is made exactly for that purpose. Create a file context_processors.py in one of your app directories, then in the file define a function that return a dictionary of variables to insert in every template context, something like this:

def add_variable_to_context(request):
    return {
        'testme': 'Hello world!'
    }

Enable your context processor in the settings (django>=1.8):

TEMPLATES = [
    {
        'BACKEND': 'django.template.backends.django.DjangoTemplates',
        'DIRS': [root('templates'),],
        'APP_DIRS': True,
        'OPTIONS': {
            'context_processors': [
                'django.template.context_processors.debug',
                'django.template.context_processors.request',
                'django.contrib.auth.context_processors.auth',
                'django.contrib.messages.context_processors.messages',
                'yourapp.context_processors.add_variable_to_context',
            ],
        },
    },
]

Then in every template you can write

{{ testme }}

And it will render as

Hello world!

More info in the Django documentation

回答2:

If you need this data in (almost) every template, then it makes sense to use a context processor. From the django docs:

The context_processors option is a list of callables – called context processors – that take a request object as their argument and return a dictionary of items to be merged into the context.

Django docs on Writing your own context processors

来源：https://stackoverflow.com/questions/34902707/how-can-i-pass-data-to-django-layouts-like-base-html-without-having-to-provi