Laravel Query Builder where max id

末鹿安然 提交于 2019-11-29 00:58:13
Tim Groeneveld

You should be able to perform a select on the orders table, using a raw WHERE to find the max(id) in a subquery, like this:

 \DB::table('orders')->where('id', \DB::raw("(select max(`id`) from orders)"))->get();

If you want to use Eloquent (for example, so you can convert your response to an object) you will want to use whereRaw, because some functions such as toJSON or toArray will not work without using Eloquent models.

 $order = Order::whereRaw('id = (select max(`id`) from orders)')->get();

That, of course, requires that you have a model that extends Eloquent.

 class Order extends Eloquent {}

As mentioned in the comments, you don't need to use whereRaw, you can do the entire query using the query builder without raw SQL.

 // Using the Query Builder
 \DB::table('orders')->find(\DB::table('orders')->max('id'));

 // Using Eloquent
 $order = Order::find(\DB::table('orders')->max('id'));

(Note that if the id field is not unique, you will only get one row back - this is because find() will only return the first result from the SQL server.).

Just like the docs say

DB::table('orders')->max('id');

For Laravel ^5

Orders::max('id');

I used it is short and best;

No need to use sub query, just Try this,Its working fine:

  DB::table('orders')->orderBy('id', 'desc')->first();

For objects you can nest the queries:

DB::table('orders')->find(DB::table('orders')->max('id'));

So the inside query looks up the max id in the table and then passes that to the find, which gets you back the object.

Based on the Laravel Documentation, the following should work:

You may call max methods after constructing your query: DB::table('orders')->max('id');

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