Sass variable default scope

眉间皱痕 提交于 2019-11-28 21:26:30

Defining $val: 'green' locally in class1 does not alter $val: 'red' !default in mixin, because it look for global $val. At this point, no global $val has been defined.

Then global $val is defined as 'black'. After this $val in mixin look for global $val. At this point, global $val has been defined as 'black'.

Defining $val again locally will alter global $val that has been defined.

@mixin foo 
  $val: 'red' !default // defined locally
  .bar
    color: $val

@include foo // $val in mixin foo look for global $val. no global $val found, then 'red'

.class1
  $val: 'green'
  @include foo // $val in mixin foo look for global $val. no global $val found, then 'red'
  color: $val // local $val 'green'
  .class11 
    @include foo // $val in mixin foo look for global $val. no global $val found, then 'red'

$val: 'black' // defined globally at the first time

.class2 
  @include foo // $val in mixin foo look for global $val. $val found, 'black'

.class3
  $val: 'blue' // change the gobal $val
  @include foo // $val in mixin foo look for global $val. $val found, 'blue'

.class4
  @include foo // $val in mixin foo look for global $val. $val found, 'blue'
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