os.mkdir(path) returns OSError when directory does not exist

Question

I am calling os.mkdir to create a folder with a certain set of generated data. However, even though the path I specified has not been created, the os.mkdir(path) raises an OSError that the path already exists.

For example, I call:

os.mkdir(test)

This call results in OSError: [Errno 17] File exists: 'test' even though I don't have a test directory or a file named test anywhere.

NOTE: the actual path name I use is not "test" but something more obscure that I'm sure is not named anywhere.

Help, please?

Answer 1

Greg's answer is correct but doesn't go far enough. OSError has sub-error conditions, and you don't want to suppress them all every time. It's prudent to trap just expected OS errors.

Do additional checking before you decide to suppress the exception, like this:

import errno
import os

try:
    os.mkdir(dirname)
except OSError as exc:
    if exc.errno != errno.EEXIST:
        raise
    pass

You probably don't want to suppress errno.EACCES (Permission denied), errno.ENOSPC (No space left on device), errno.EROFS (Read-only file system) etc. Or maybe you do want to -- but that needs to be a conscious decision based on the specific logic of what you're building.

Greg's code suppresses all OS errors; that's unsafe just like except Exception is unsafe.

Answer 2

Just check if the path exist. if not create it

if not os.path.exists(test):
        os.makedirs(test)

Answer 3

In Python 3.2 and above, you can use:

os.makedirs(path, exist_ok=True)

to avoid getting an exception if the directory already exists. This will still raise an exception if path exists and is not a directory.

Answer 4

I also faced the same problem, specially, when the string 'test' contains the multiple directory name. So when 'test' contains the single directory -

if not os.path.exists(test):
    try:
        os.makedir(test)
    except:
        raise OSError("Can't create destination directory (%s)!" % (test))  

If the 'test' contains multiple directory like '\dir1\dir2' then -

if not os.path.exists(test):
    try:
        os.makedirs(test)
    except:
        raise OSError("Can't create destination directory (%s)!" % (test))  

Answer 5

I don't know the specifics of your file system. But if you really want to get around this maybe use a try/except clause?

try:
    os.mkdir(test)
except OSError:
    print "test already exists"

You can always do some kind of debugging in the meanwhile.

Answer 6

You have a file there with the name test. You can't make a directory with that exact same name.

Answer 7

Happened to me on Windows, maybe this is the case:

Like you I was trying to :

os.mkdir(dirname)

and got OSError: [Errno 17] File exists: '<dirname>'. When I ran:

os.path.exists(dirname)

I got false, and it drove me mad for a while :)

The problem was: In a certain window I was at the specific directory. Even though it did not exists at that time (I removed it from linux). The solution was to close that window \ navigate to somewhere else. Shameful, I know ...

Answer 8

Maybe there's a hidden folder named test in that directory. Manually check if it exists.

ls -a

Create the file only if it doesn't exist.

if not os.path.exists(test):
    os.makedirs(test)