SHOW TABLES statement with multiple LIKE values

问题

mysql> SHOW TABLES like 'cms';
+-------------------------+
| Tables_in_tianyan (cms) |
+-------------------------+
| cms                     |
+-------------------------+
1 row in set (0.00 sec)

Result

mysql> SHOW TABLES like 'cms' or like 'role';
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual...

How can I filter by multiple conditions ?

回答1:

You need to use the WHERE clause. As shown in the docs, you can only have a single pattern if you use "SHOW TABLES LIKE ...", but you can use an expression in the WHERE clause if you use "SHOW TABLES WHERE ...". Since you want an expression, you need to use the WHERE clause.

SHOW TABLES
FROM `<yourdbname>`
WHERE 
    `Tables_in_<yourdbname>` LIKE '%cms%'
    OR `Tables_in_<yourdbname>` LIKE '%role%';

回答2:

You can just use a normal SQL WHERE statement to do it.

SHOW TABLES WHERE Tables_in_tianyan LIKE '%cms%'

回答3:

show tables from mydb 
where 
  Tables_in_mydb like '%statistics%' 
  or Tables_in_mydb like '%device%';

回答4:

You take table list using the below code

select TABLE_NAME from information_schema.TABLES where TABLE_SCHEMA = 'database_name' 

Hope it will help you.

来源：https://stackoverflow.com/questions/5609620/show-tables-statement-with-multiple-like-values