Xpath expression with multiple predicates

自作多情 提交于 2019-11-28 19:06:20

The following should do what you're after:

/root/user[login='user1' and 
           name='User 1' and 
           profile='admin' and
           profile='operator']

Having two tests for the profile value might seem odd, but as there are multiple profile nodes then the condition will be satisfied as long as at least one node matches the test.

The reason you can compare profile directly to a string, even though it actually is a node is that the string-value of an element node is the string-value of all its descendants concatenated together, which in this case is just the contents of value.

If profile contained more elements than value you'd have to use a slightly more complex predicate test to determine the existence of a matching profile node based just on the value (this should work with your updated question):

/root/user[login='user1' and 
           name='User 1' and 
           profile[value='admin'] and
           profile[value='operator']]

Here is a more exact answer (at present Greg Beech's answer does not check for condition 3. in the problem: the user element must have exactly 2 profile children):

/*/user
        [login='user1' 
        and            
         name='User 1' 
        and  
         not(profile[3])
        and          
         profile/value='admin' 
        and           
         profile/value='operator'
         ]

Assuming users is the root:

/users/user[login='user1' and name='User 1' 
            and (profile='admin' and profile='operator')]
Ankush Jetly
/root/user[login='user1' and name='User 1' and profile/value='admin' and profile/value='operator'
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