Date format for plotting x axis ticks of time series data

拟墨画扇 提交于 2019-11-28 19:01:23
A5C1D2H2I1M1N2O1R2T1

Perhaps you are not using as.yearmon() correctly, because the following works for me (using dat from Gavin's answer):

library(zoo)
dat$date <- as.yearmon(dat$date, "%YM%m")

Thus, working through to getting things to plot correctly:

  1. Your data:

    dat <- read.table(text = "date    x   x2
    1975M1  112.44  113.12
    1975M2  113.1   114.36
    1975M3  115.04  114.81
    1975M4  117.65  115.35
    1975M5  119.5   116.92
    1975M6  121.4   118.56
    1975M7  120.64  118.97
    1975M8  119.12  119.84
    1975M9  118.91  120.59
    1975M10 120.58  122.3
    1975M11 121.26  123.35
    1975M12 122.34  123.33", header = TRUE)
    
  2. Conversion to xts using as.yearmon() from the "zoo" package.

    library(xts) # Will also load zoo
    dat.xts <- xts(dat[-1], 
                   order.by = as.yearmon(dat$date, "%YM%m"))
    dat.xts
    #               x     x2
    # Jan 1975 112.44 113.12
    # Feb 1975 113.10 114.36
    # Mar 1975 115.04 114.81
    # Apr 1975 117.65 115.35
    # May 1975 119.50 116.92
    # Jun 1975 121.40 118.56
    # Jul 1975 120.64 118.97
    # Aug 1975 119.12 119.84
    # Sep 1975 118.91 120.59
    # Oct 1975 120.58 122.30
    # Nov 1975 121.26 123.35
    # Dec 1975 122.34 123.33
    
  3. Plotting your data:

    plot.zoo(dat.xts)
    

    plot.zoo(dat.xts, 
             plot.type="single", 
             col = c("red", "blue"))
    

Update: Specifying your own axes

Here is some sample data to work with (it's usually nice to share such sample data when asking questions on SO since it makes it easier for others to replicate and address your problem(s)). Note that for this example, we've skipped using the "xts" package since it's not really necessary.

set.seed(1)
dat <- data.frame(date = paste0(rep(1975:1977, each = 12), 
                                "M", rep(1:12, times = 3)),
                  x1 = runif(36, min = 100, max = 140),
                  x2 = runif(36, min = 100, max = 140))
library(zoo) # xts is actually unnecessary if this is all you're doing
# Convert your data to a `zoo` object
dat.z <- zoo(dat[-1], order.by = as.yearmon(dat$date, "%YM%m"))

This is the default plot obtained with plot(dat.z, screen = 1, col = 1:2):

From your comments, it sounds like you want something like monthly labels.

  1. Plot the data, but suppress the x-axis with xaxt = "n"

    plot(dat.z, screen = 1, col = 1:2, xaxt = "n")
    
  2. Do some setup work to have a label for every month. (See ?plot.zoo, from where this is modified.)

    tt <- time(dat.z)
    # The following is just the sequence 1:36. 
    #   If you wanted only every third month plotted,
    #   use a sequence like ix <- seq(1, length(tt), 3)
    ix <- seq_along(tt) 
    # What format do you want for your labels.
    #   This yields abbreviated month - abbreviated year
    fmt <- "%b-%y" 
    labs <- format(tt, fmt) # Generate the vector of your labels
    
  3. Add your axis to your plot. Some experimentation might be needed to find the right sizes for everything. las = 2 makes the labels perpendicular to the axis, which is required if you really feel the need to include a label for every month of each year.

    axis(side = 1, at = tt[ix], labels = labs[ix], 
         tcl = -0.7, cex.axis = 0.7, las = 2)
    

Here is the final plot:

By the way, if you are getting dates like 1977.15 and so on, you might want to read through some of the answers to this question, for example, looking at @joran's use of pretty().

Using your data:

dat <- read.table(text = "date    x   x2
1975M1  112.44  113.12
1975M2  113.1   114.36
1975M3  115.04  114.81
1975M4  117.65  115.35
1975M5  119.5   116.92
1975M6  121.4   118.56
1975M7  120.64  118.97
1975M8  119.12  119.84
1975M9  118.91  120.59
1975M10 120.58  122.3
1975M11 121.26  123.35
1975M12 122.34  123.33", header = TRUE)

The thing you are missing is that you need to add a day to your dates in order for them to be valid input for as.Date(). This bit can be done by appending "-01" to each element of date. We need to add the "-" separator to clearly demarcate the month from the new day we are adding.

paste0(as.character(date), "-01") ## temporary step, not needed

Now we have something that resembles

> with(dat, paste0(date, "-01"))  ## temporary step, not needed
 [1] "1975M1-01"  "1975M2-01"  "1975M3-01"  "1975M4-01"  "1975M5-01" 
 [6] "1975M6-01"  "1975M7-01"  "1975M8-01"  "1975M9-01"  "1975M10-01"
[11] "1975M11-01" "1975M12-01"

We can write out an appropriate format that as.Date() can use: "%YM%m-%d". Note here we include a literal "M" and the separator before the day part "-".

Putting this altogether with transform() to insert the result back into dat we have:

## full solution
dat <- transform(dat, date = as.Date(paste0(date, "-01"), format = "%YM%m-%d"))

Which gives

> dat
         date      x     x2
1  1975-01-01 112.44 113.12
2  1975-02-01 113.10 114.36
3  1975-03-01 115.04 114.81
4  1975-04-01 117.65 115.35
5  1975-05-01 119.50 116.92
6  1975-06-01 121.40 118.56
7  1975-07-01 120.64 118.97
8  1975-08-01 119.12 119.84
9  1975-09-01 118.91 120.59
10 1975-10-01 120.58 122.30
11 1975-11-01 121.26 123.35
12 1975-12-01 122.34 123.33
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