问题
I have to write a script that finds all executable files in a directory. So I tried several ways to implement it and they actually work. But I wonder if there is a nicer way to do so.
So this was my first approach:
ls -Fla | grep \*$
This works fine, because the -F flag does the work for me and adds to each executable file an asterisk, but let's say I don't like the asterisk sign.
So this was the second approach:
ls -la | grep -E ^-.{2}x
This too works fine, I want a dash as first character, then I'm not interested in the next two characters and the fourth character must be a x.
But there's a bit of ambiguity in the requirements, because I don't know whether I have to check for user, group or other executable permission. So this would work:
ls -la | grep -E ^-.{2}x\|^-.{5}x\|^-.{8}x
So I'm testing the fourth, seventh and tenth character to be a x.
Now my real question, is there a better solution using ls and grep with regex to say:
I want to grep only those files, having at least one x in the ten first characters of a line produced by ls -la
回答1:
Do you need to use ls? You can use find to do the same:
find . -maxdepth 1 -perm -111 -type f
will return all executable files in the current directory. Remove the -maxdepth flag to traverse all child directories.
You could try this terribleness but it might match files that contain strings that look like permissions.
ls -lsa | grep -E "[d\-](([rw\-]{2})x){1,3}"
回答2:
If you absolutely must use ls and grep, this works:
ls -Fla | grep '^\S*x\S*'
It matches lines where the first word (non-whitespace) contains at least one 'x'.
Find is the perfect tool for this. This finds all files (-type f) that are executable:
find . -type f -executable
If you don't want it to recursively list all executables, use maxdepth:
find . -maxdepth 1 -type f -executable
回答3:
Perhaps with test -x?
for f in $(\ls) ; do test -x $f && echo $f ; done
The \ on ls will bypass shell aliases.
回答4:
for i in `ls -l | awk '{ if ( $1 ~ /x/ ) {print $NF}}'`; do echo `pwd`/$i; done
This gives absolute paths to the executables.
回答5:
file * |grep "ELF 32-bit LSB executable"|awk '{print $1}'
来源：https://stackoverflow.com/questions/7812324/finding-executable-files-using-ls-and-grep