I am making a stopwatch type program in python and I would like to know how to detect if a key is pressed (such as p for pause and s for stop), and I would not like it to be something like raw_input that waits for the user's input before continuing execution. Anyone know how to do this in a while loop?
Also, I would like to make this cross-platform, but if that is not possible, then my main development target is linux
Python has a keyboard module with many features. Install it, perhaps with this command:
pip3 install keyboard
Then use it in code like:
import keyboard # using module keyboard
while True: # making a loop
try: # used try so that if user pressed other than the given key error will not be shown
if keyboard.is_pressed('q'): # if key 'q' is pressed
print('You Pressed A Key!')
break # finishing the loop
else:
pass
except:
break # if user pressed a key other than the given key the loop will break
As OP mention about raw_input - that means he want cli solution. Linux: curses is what you want (windows PDCurses). Curses, is an graphical API for cli software, you can achieve more than just detect key events.
This code will detect keys until new line is pressed.
import curses
import os
def main(win):
win.nodelay(True)
key=""
win.clear()
win.addstr("Detected key:")
while 1:
try:
key = win.getkey()
win.clear()
win.addstr("Detected key:")
win.addstr(str(key))
if key == os.linesep:
break
except Exception as e:
# No input
pass
curses.wrapper(main)
For those who are on windows and were struggling to find an working answer here's mine: pynput
from pynput.keyboard import Key, Listener
def on_press(key):
print('{0} pressed'.format(
key))
def on_release(key):
print('{0} release'.format(
key))
if key == Key.esc:
# Stop listener
return False
# Collect events until released
with Listener(
on_press=on_press,
on_release=on_release) as listener:
listener.join()
The function above will print whichever key you are pressing plus start an action as you release the 'esc' key. The keyboard documentation is here for a more variated usage.
For Windows you could use msvcrt
like this:
import msvcrt
while True:
if msvcrt.kbhit():
key = msvcrt.getch()
print(key) # just to show the result
Use PyGame to have a window and then you can get the key events.
For the letter p
:
import pygame, sys
import pygame.locals
pygame.init()
BLACK = (0,0,0)
WIDTH = 1280
HEIGHT = 1024
windowSurface = pygame.display.set_mode((WIDTH, HEIGHT), 0, 32)
windowSurface.fill(BLACK)
while True:
for event in pygame.event.get():
if event.key == pygame.K_p:
#Do what you want to here
pass
if event.type == pygame.locals.QUIT:
pygame.quit()
sys.exit()
Use this code for find the which key pressed
from pynput import keyboard
def on_press(key):
try:
print('alphanumeric key {0} pressed'.format(
key.char))
except AttributeError:
print('special key {0} pressed'.format(
key))
def on_release(key):
print('{0} released'.format(
key))
if key == keyboard.Key.esc:
# Stop listener
return False
# Collect events until released
with keyboard.Listener(
on_press=on_press,
on_release=on_release) as listener:
listener.join()
I would suggest you use PyGame and add an event handle.
So I made this ..kind of game.. based on this post (using msvcr library and Python 3.7).
The following is the "main function" of the game, that is detecting the keys pressed:
# Requiered libraries - - - -
import msvcrt
# - - - - - - - - - - - - - -
def _secret_key(self):
# Get the key pressed by the user and check if he/she wins.
bk = chr(10) + "-"*25 + chr(10)
while True:
print(bk + "Press any key(s)" + bk)
#asks the user to type any key(s)
kp = str(msvcrt.getch()).replace("b'", "").replace("'", "")
# Store key's value.
if r'\xe0' in kp:
kp += str(msvcrt.getch()).replace("b'", "").replace("'", "")
# Refactor the variable in case of multi press.
if kp == r'\xe0\x8a':
# If user pressed the secret key, the game ends.
# \x8a is CTRL+F12, that's the secret key.
print(bk + "CONGRATULATIONS YOU PRESSED THE SECRET KEYS!\a" + bk)
print("Press any key to exit the game")
msvcrt.getch()
break
else:
print(" You pressed:'", kp + "', that's not the secret key(s)\n")
if self.select_continue() == "n":
if self.secondary_options():
self._main_menu()
break
If you want the full source code of the porgram you can see it or download it from here:
(note: the secret keypress is: CTRL+F12)
I hope you can serve as an example and help for those who come to consult this information.
Greetings!
key = cv2.waitKey(1)
This is from the openCV package. It detects a keypress without waiting.
来源:https://stackoverflow.com/questions/24072790/detect-key-press-in-python