问题
Possible Duplicate:
Why can't I return a double from two ints being divided
My C++ program is truncating the output of my integer devision even when I try and place the output into a float. How can I prevent this whilst keeping those to variables (a & b) as integers?
user@box:~/c/precision$ cat precision.cpp
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
int a = 10, b = 3;
float ans = (a/b);
cout<<fixed<<setprecision(3);
cout << (a/b) << endl;
cout << ans << endl;
return 0;
}
user@box:~/c/precision$ g++ -o precision precision.cpp
user@box:~/c/precision$ ./precision
3
3.000
回答1:
Cast the operands to floats:
float ans = (float)a / (float)b;
来源：https://stackoverflow.com/questions/12447325/dividing-two-integers-to-produce-a-float-result